Theory of Structures The equivalent length is of a column of length having both the ends fixed, is L l L/2 2 L L l L/2 2 L ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For beams of uniform strength, if depth is constant, Width b 3 M Width b M Width b 1/M Width b M 2 Width b 3 M Width b M Width b 1/M Width b M 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A compound bar consists of two bars of equal length. Steel bar cross -section is 3500 mm²and that of brass bar is 3000 mm². These are subjected to a compressive load 100,000 N. If Eb = 0.2 MN/mm² and Eb = 0.1 MN/mm², the stresses developed are: b = 5 N/mm² s = 10 N/mm² b = 10 N/mm² s = 20 N/mm 2 b = 6 N/mm² s = 12 N/mm² b = 8 N/mm² s = 16 N/mm² b = 5 N/mm² s = 10 N/mm² b = 10 N/mm² s = 20 N/mm 2 b = 6 N/mm² s = 12 N/mm² b = 8 N/mm² s = 16 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A square column carries a load P at the centroid of one of the quarters of the square. If a is the side of the main square, the combined bending stress will be 3p/a² 2p/a² 4p/a² p/a² 3p/a² 2p/a² 4p/a² p/a² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In plastic analysis, the shape factor for a circular section, is 1.2 1.5 1.3 1.7 1.2 1.5 1.3 1.7 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y I/M = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
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