Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 3/2 2/3 5/8 8/5 3/2 2/3 5/8 8/5 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Radius of gyration divided by area of cross-section Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration Radius of gyration divided by area of cross-section Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the length and diameter of a simply supported uniform circular beam which experiences maximum bending stress equal to tensile stress due to same load at its mid span, is 1/2 1/3 1/4 1/8 1/2 1/3 1/4 1/8 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For determining the support reactions at A and B of a three hinged arch, points B and Care joined and produced to intersect the load line at D and a line parallel to the load line through A at D’. Distances AD, DD’ and AD’ when measured were 4 cm, 3 cm and 5 cm respectively. The angle between the reactions at A and B is 30° 45° 90° 60° 30° 45° 90° 60° ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length 2 cm and depth 10 cm tapers in plan from a width 24 cm to zero at its free end. If the modulus of elasticity of the material is 0.2 × 106 N/mm², the deflection of the free end, is 5 mm 4 mm 2 mm 3 mm 5 mm 4 mm 2 mm 3 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 3K (1 – 2/m) All of these E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
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