Theory of Structures Slenderness ratio of a long column, is Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration Area of cross-section divided by least radius of gyration Area of cross-section divided by radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel rod of sectional area 250 sq. mm connects two parallel walls 5 m apart. The nuts at the ends were tightened when the rod was heated to 100°C. If steel = 0.000012/C°, Esteel = 0.2 MN/mm², the tensile force developed at a temperature of 50°C, is 120 N/mm² 100 N/mm 2 80 N/mm² 150 N/mm² 120 N/mm² 100 N/mm 2 80 N/mm² 150 N/mm² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If a solid shaft (diameter 20 cm, length 400 cm, N = 0.8 × 105 N/mm²) when subjected to a twisting moment, produces maximum shear stress of 50 N/mm 2, the angle of twist in radians, is 0.0025 0.003 0.001 0.002 0.0025 0.003 0.001 0.002 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The area of the core of a column of cross sectional area A, is (1/3) A (1/6) A (1/12) A (1/18) A (1/3) A (1/6) A (1/12) A (1/18) A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is (1 – g/f)/A [W (2 + f/G)]/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A (1 – g/f)/A [W (2 + f/G)]/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 2j – 3 j = 3m – 2 m = 3j – 2 j = 2m – 3 m = 2j – 3 j = 3m – 2 m = 3j – 2 j = 2m – 3 ANSWER DOWNLOAD EXAMIANS APP
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