Theory of Structures A steel rod 1 metre long having square cross section is pulled under a tensile load of 8 tonnes. The extension in the rod was 1 mm only. If Esteel = 2 × 106 kg/cm², the side of the rod, is 1 cm 2.5 cm 2 cm 1.5 cm 1 cm 2.5 cm 2 cm 1.5 cm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) A uniformly distributed load w/unit length An isolated load at mid span A load varying linearly from zero at one end to w at the other end None of these A uniformly distributed load w/unit length An isolated load at mid span A load varying linearly from zero at one end to w at the other end None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 20 mm in diameter simply-supported at its ends over a total span of 40 cm carries a load at its centre. If the maximum stress induced in the bar is limited to N/mm², the bending strain energy stored in the bar, is 711 N mm 511 N mm 611 N mm 411 N mm 711 N mm 511 N mm 611 N mm 411 N mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the length and diameter of a simply supported uniform circular beam which experiences maximum bending stress equal to tensile stress due to same load at its mid span, is 1/4 1/3 1/8 1/2 1/4 1/3 1/8 1/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum bending moment for a simply supported beam with a uniformly distributed load w/unit length, is WI²/12 WI²/4 WI²/8 WI/2 WI²/12 WI²/4 WI²/8 WI/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y ANSWER DOWNLOAD EXAMIANS APP
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