Theory of Structures A truss containing j joints and m members, will be a simple truss if j = 2m – 3 j = 3m – 2 m = 2j – 3 m = 3j – 2 j = 2m – 3 j = 3m – 2 m = 2j – 3 m = 3j – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of crippling loads of a column having both the ends fixed to the column having both the ends hinged, is 4 2 1 3 4 2 1 3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Gradually applied static loads do not change with time their All of these Magnitude Point of application Direction All of these Magnitude Point of application Direction ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum tensile stress at the section Depth of the section Depth of the neutral axis Maximum compressive stress at the section Maximum tensile stress at the section Depth of the section Depth of the neutral axis Maximum compressive stress at the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A lift of weight W is lifted by a rope with an acceleration f. If the area of cross-section of the rope is A, the stress in the rope is [W (1 + f/ G)]/ A [W (2 + g/f)]/A [W (2 + f/G)]/A (1 – g/f)/A [W (1 + f/ G)]/ A [W (2 + g/f)]/A [W (2 + f/G)]/A (1 – g/f)/A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 3K (1 – 2/m) E = 2N (1 + 1/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 3K (1 – 2/m) E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
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