Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 2j – 3 j = 2m – 3 j = 3m – 2 m = 3j – 2 m = 2j – 3 j = 2m – 3 j = 3m – 2 m = 3j – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good All of these E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 2N (1 + 1/m) All of these E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length 2 cm and depth 10 cm tapers in plan from a width 24 cm to zero at its free end. If the modulus of elasticity of the material is 0.2 × 106 N/mm², the deflection of the free end, is 5 mm 3 mm 4 mm 2 mm 5 mm 3 mm 4 mm 2 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A steel bar 20 mm in diameter simply-supported at its ends over a total span of 40 cm carries a load at its centre. If the maximum stress induced in the bar is limited to N/mm², the bending strain energy stored in the bar, is 411 N mm 511 N mm 711 N mm 611 N mm 411 N mm 511 N mm 711 N mm 611 N mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum magnitude of shear stress due to shear force F on a rectangular section of area A at the neutral axis, is F/2A F/A 2F/3A 3F/2A F/2A F/A 2F/3A 3F/2A ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the maximum deflections of a simply supported beam with a central load W and of a cantilever of same length and with a load W at its free end, is 1/10 1/8 1/16 1/12 1/10 1/8 1/16 1/12 ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS