Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 3j – 2 m = 2j – 3 j = 2m – 3 j = 3m – 2 m = 3j – 2 m = 2j – 3 j = 2m – 3 j = 3m – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of crippling loads of a column having both the ends fixed to the column having both the ends hinged, is 4 1 2 3 4 1 2 3 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 250 mm 300 mm 400 mm 200 mm 250 mm 300 mm 400 mm 200 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of shear stress and shear strain of an elastic material, is Both A. and B. Modulus of Rigidity Modulus of Elasticity Shear Modulus Both A. and B. Modulus of Rigidity Modulus of Elasticity Shear Modulus ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 3/2 8/5 2/3 5/8 3/2 8/5 2/3 5/8 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = F/Y M/I = R/E = F/Y M/I = E/R = Y/F I/M = R/E = F/Y M/I = E/R = F/Y M/I = R/E = F/Y M/I = E/R = Y/F I/M = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
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