Theory of Structures A truss containing j joints and m members, will be a simple truss if m = 2j – 3 j = 2m – 3 j = 3m – 2 m = 3j – 2 m = 2j – 3 j = 2m – 3 j = 3m – 2 m = 3j – 2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The strain energy stored in a spring when subjected to greatest load without being permanently distorted, is called Stiffness Proof load Proof stress Proof resilience Stiffness Proof load Proof stress Proof resilience ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection of a simply supported beam of span L, carrying an isolated load at the centre of the span; flexural rigidity being EI, is WL3/24EL WL3/48EL WL3/3EL WL3/8EL WL3/24EL WL3/48EL WL3/3EL WL3/8EL ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then M/I = E/R = F/Y M/I = R/E = F/Y M/I = E/R = Y/F I/M = R/E = F/Y M/I = E/R = F/Y M/I = R/E = F/Y M/I = E/R = Y/F I/M = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 2h/l² × (1 – x) y = 3h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum compressive stress at the section Depth of the section Depth of the neutral axis Maximum tensile stress at the section Maximum compressive stress at the section Depth of the section Depth of the neutral axis Maximum tensile stress at the section ANSWER DOWNLOAD EXAMIANS APP
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