Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) None of these An isolated load at mid span A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end None of these An isolated load at mid span A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For beams of uniform strength, if depth is constant, Width b M 2 Width b M Width b 3 M Width b 1/M Width b M 2 Width b M Width b 3 M Width b 1/M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection of a simply supported beam of span L, carrying an isolated load at the centre of the span; flexural rigidity being EI, is WL3/3EL WL3/24EL WL3/8EL WL3/48EL WL3/3EL WL3/24EL WL3/8EL WL3/48EL ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures a uniform circular bar of diameter d and length , which extends by an The deflection of amount under a tensile pull , when it carries the same load at its mid-span, is ee²l/3d² e²l²/3d² el/2d el²/3d² ee²l/3d² e²l²/3d² el/2d el²/3d² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures section modulus of a square section of side B and that of a circular section of the ratio of the diameter D, is 3 /8 3 /16 /16 2 /15 3 /8 3 /16 /16 2 /15 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Radius of gyration divided by area of cross-section Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
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