Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end An isolated load at mid span None of these A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end An isolated load at mid span None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures a uniform circular bar of diameter d and length , which extends by an The deflection of amount under a tensile pull , when it carries the same load at its mid-span, is el²/3d² el/2d ee²l/3d² e²l²/3d² el²/3d² el/2d ee²l/3d² e²l²/3d² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Inertia of a rectangular section of width and depth about an axis passing the moment of through C.G. and parallel to its width is BD²/6 BD³/12 B²D/6 BD³/6 BD²/6 BD³/12 B²D/6 BD³/6 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y I/M = R/E = F/Y M/I = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A close coil helical spring of mean diameter D consists of n coils of diameter d. If it carries an axial load W, the energy stored in the spring, is 4WD²n/d4N 4W²D3n/d4N 4W²D3n²/d4N 4W²Dn/d4N 4WD²n/d4N 4W²D3n/d4N 4W²D3n²/d4N 4W²Dn/d4N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam carries varying load from zero at one end and w at the other end. If the length of the beam is a, the maximum bending moment will be wa/27 w²a wa²/27 wa² wa/27 w²a wa²/27 wa² ANSWER DOWNLOAD EXAMIANS APP
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