Machine Design The endurance limit in shear of carbon steel can be obtained by multiplying the endurance limit in flexure by a factor of 0.45 0.75 0.55 0.65 0.45 0.75 0.55 0.65 ANSWER DOWNLOAD EXAMIANS APP
Machine Design A closely coiled helical spring is acted upon by an axial force. The maximum shear stress developed in the spring is τ. The half of the length of the spring if cut off and the remaining spring is acted upon by the same axial force. The maximum shear stress in the spring in new condition will be τ/2 4 τ τ 2 τ τ/2 4 τ τ 2 τ ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is 2100 N-m 2136 N-m 2050 N-m 2000 N-m 2100 N-m 2136 N-m 2050 N-m 2000 N-m ANSWER DOWNLOAD EXAMIANS APP
Machine Design When two helical springs of equal lengths are arranged to form a cluster spring, then Only A is correct Both A and B is correct Shear stress in each spring will be equal Load taken by each spring will be half the total load Only A is correct Both A and B is correct Shear stress in each spring will be equal Load taken by each spring will be half the total load ANSWER DOWNLOAD EXAMIANS APP
Machine Design The centre to centre distance between two consecutive rivets in a row, is called Diagonal pitch Back pitch Margin Pitch Diagonal pitch Back pitch Margin Pitch ANSWER DOWNLOAD EXAMIANS APP
Machine Design A shaft is subjected to fluctuating loads for which the normal torque (T) and bending moment (M) are 1000 N-m and 500 N-m respectively. If the combined shock and fatigue factor for bending is 1.5 and combined shock and fatigue factor for torsion is 2, then the equivalent twisting moment for the shaft is 2100 N-m 2136 N-m 2000 N-m 2050 N-m 2100 N-m 2136 N-m 2000 N-m 2050 N-m ANSWER DOWNLOAD EXAMIANS APP
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