Hydraulics and Fluid Mechanics in ME The efficiency of jet propulsion for a ship with inlet orifices at right angles to the direction of motion of ship is given by [2(Vr + v) v]/ Vr² [2(Vr - v) v]/ Vr² [(Vr + v) v]/ Vr [(Vr - v) v]/ Vr [2(Vr + v) v]/ Vr² [2(Vr - v) v]/ Vr² [(Vr + v) v]/ Vr [(Vr - v) v]/ Vr ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME For 450 m head of water, _________ shall be used. Pelton wheel None of these Kaplan turbine Francis turbine Pelton wheel None of these Kaplan turbine Francis turbine ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The center of pressure of a surface subjected to fluid pressure is the point on the surface at which gravitational force acis at which all hydraulic forces meet similar to metacentre on the surface at which resultant pres-sure acts on the surface at which gravitational force acis at which all hydraulic forces meet similar to metacentre on the surface at which resultant pres-sure acts ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Francis turbine is best suited for All types of heads High head installation above 180 m Medium head application from 24 to 180 m Low head installation up to 30 m All types of heads High head installation above 180 m Medium head application from 24 to 180 m Low head installation up to 30 m ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A body floats in stable equilibrium When its e.g. is below its center of buoyancy When the metacentre is above e.g. When its meatcentric height is zero Metacentre has nothing to do with position of e.g. for determining stability When its e.g. is below its center of buoyancy When the metacentre is above e.g. When its meatcentric height is zero Metacentre has nothing to do with position of e.g. for determining stability ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge over a rectangular notch is (where b = Width of notch, and H = Height of liquid, above the sill of the notch) (2/3) Cd × b × √(2g) × H (2/3) Cd × b × √(2gH) (2/3) Cd × b × √(2g) × H3/2 (2/3) Cd × b × √(2g) × H2 (2/3) Cd × b × √(2g) × H (2/3) Cd × b × √(2gH) (2/3) Cd × b × √(2g) × H3/2 (2/3) Cd × b × √(2g) × H2 ANSWER DOWNLOAD EXAMIANS APP
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