Machine Design The contact ratio for gears is Less than one Zero Greater than one None of these Less than one Zero Greater than one None of these ANSWER DOWNLOAD EXAMIANS APP
Machine Design If P1 and P2 are the tight and slack side tensions in the belt, then the initial tension Pi (according to Barth) will be equal to (Where, Pc is centrifugal tension) [(√P1 + √P2)/2]² ⅟₂× (P1 + P2) P1 + P2 [⅟₂ × (P1 + P2)] + Pc [(√P1 + √P2)/2]² ⅟₂× (P1 + P2) P1 + P2 [⅟₂ × (P1 + P2)] + Pc ANSWER DOWNLOAD EXAMIANS APP
Machine Design The ratio of belt tensions (p1/p2) considering centrifugal force in flat belt is given byWhere m = mass of belt per meter (kg/m)v = belt velocity (m/s)f = coefficient of frictiona = angle of wrap (radians) P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα P1 / P2 = e–ᶠα P1 / P2 = eᶠα (P1 - mv²)/ (P2 - mv²) = e–ᶠα (P1 - mv²)/ (P2 - mv²) = eᶠα ANSWER DOWNLOAD EXAMIANS APP
Machine Design The connecting rod bolts are tightened up so that tightening stress Is 50% of yield point Is just sufficient to hold parts together Is about yield point divided by safety factor Approaches yield point Is 50% of yield point Is just sufficient to hold parts together Is about yield point divided by safety factor Approaches yield point ANSWER DOWNLOAD EXAMIANS APP
Machine Design Lewis equation is applied Only to the gear Only to the pinion To stronger of the pinion or gear To weaker of the pinion or gear Only to the gear Only to the pinion To stronger of the pinion or gear To weaker of the pinion or gear ANSWER DOWNLOAD EXAMIANS APP
Machine Design When an open coiled helical compression spring is subjected to an axial compressive load, the maximum shear stress induced in the wire is (where D = Mean diameter of the spring coil, d = Diameter of the spring wire, K = Wahl's stress factor, and W = Axial compressive load on the spring) (WD/ πd3) × K (8WD/ πd3) × K (4WD/ πd3) × K (2WD/ πd3) × K (WD/ πd3) × K (8WD/ πd3) × K (4WD/ πd3) × K (2WD/ πd3) × K ANSWER DOWNLOAD EXAMIANS APP
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