Mass Transfer The change in enthalpy, when a unit quantity of gas is absorbed by relatively large quantity of adsorbent (on which a definite concentration of the adsorbed gas already exists) is termed as the Heat of wetting None of these Integral heat of adsorption Differential heat of adsorption Heat of wetting None of these Integral heat of adsorption Differential heat of adsorption ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer In physical terms, Schmidt number means Thermal diffusivity/momentum diffusivity Mass diffusivity/thermal diffusivity Thermal diffusivity/mass diffusivity Momentum diffusivity/mass diffusivity Thermal diffusivity/momentum diffusivity Mass diffusivity/thermal diffusivity Thermal diffusivity/mass diffusivity Momentum diffusivity/mass diffusivity ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Absorption accompanied with chemical reaction is exemplified by the absorption of Ammonia in water Benzol present in coke oven gas by wash oil SO₂ in alkaline solution All of these Ammonia in water Benzol present in coke oven gas by wash oil SO₂ in alkaline solution All of these ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer In case of absorption with exothermic reaction, for fluids having Both A & B Pr = Sc = 1; total mass, momentum and thermal diffusivity will be the same Pr = Sc ; there won Pr = Sc; percentage change in heat and mass transfer flux will be the same for a given change in the degree of turbulence Both A & B Pr = Sc = 1; total mass, momentum and thermal diffusivity will be the same Pr = Sc ; there won Pr = Sc; percentage change in heat and mass transfer flux will be the same for a given change in the degree of turbulence ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer Raoult's law is applicable to the Non-ideal gases Ideal solutions Real solutions Mixture of water and alcohol Non-ideal gases Ideal solutions Real solutions Mixture of water and alcohol ANSWER DOWNLOAD EXAMIANS APP
Mass Transfer The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc & Km are M.T.C. for equimolar counter diffusion with concentration & mole fraction respectively as the driving force. and, Kp = M.T.C. for diffusion of a gas through a stagnant inert gas with pressure as driving force.) Kc = Kp/RT = Km . RT/P Kc = Kp = Km None of these Kc = Kp . RT = Km . RT/p Kc = Kp/RT = Km . RT/P Kc = Kp = Km None of these Kc = Kp . RT = Km . RT/p ANSWER DOWNLOAD EXAMIANS APP