Theory of Machine The Bifilar suspension method is used to determine Natural frequency of vibration Moment of inertia Centripetal acceleration Position of balancing weights Natural frequency of vibration Moment of inertia Centripetal acceleration Position of balancing weights ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When two pulleys are connected by means of a cross belt drive, then both the pulleys will rotate in _________ directions. Same Perpendicular Opposite None of these Same Perpendicular Opposite None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The acceleration of the reciprocating roller follower when it has contact with the straight flanks of the tangent cam, is given by ω². (r₁ + r₂). (1 + cos² θ) ω². (r₁ + r₂). [(2 - cos² θ)/cos³ θ] ω². (r₁ - r₂). (1 - sin² θ) ω². (r₁ r₂). (1 - cos² θ) ω². (r₁ + r₂). (1 + cos² θ) ω². (r₁ + r₂). [(2 - cos² θ)/cos³ θ] ω². (r₁ - r₂). (1 - sin² θ) ω². (r₁ r₂). (1 - cos² θ) ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine In the below figure, PC is the connecting rod and OC is the crank making an angle θ with the line of stroke PO and rotates with uniform angular velocity at ω rad/s. The Klien's acceleration diagram for determining the acceleration of the piston P is shown by quadrilateral CQNO, the acceleration of the piston is _________ when the crank OC and connecting rod PC are at right angles to each other. Any -ve value Infinity Any +ve value Zero Any -ve value Infinity Any +ve value Zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine When the crank is at the inner dead centre, in a reciprocating steam engine, then the velocity of the piston will be None of these Maximum Minimum Zero None of these Maximum Minimum Zero ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The frictional torque transmitted in a flat collar bearing, considering uniform wear, is (where r₁ and r₂ = External and internal radii of collar respectively) (1/2) μ W (r₁ + r₂) (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3) μ W (r₁ + r₂) (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (1/2) μ W (r₁ + r₂) (2/3) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] (2/3) μ W (r₁ + r₂) (1/2) μ W [(r₁³ - r₂³)/(r₁² - r₂²)] ANSWER DOWNLOAD EXAMIANS APP
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