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Area Problems

Area Problems
The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height?

12 cm
13 cm
14 cm
16 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let height =x Then, base =2x 2x * x = 338 =>x=13

Area Problems
A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 6: 5 . The smaller side of the rectangle is?

30 cm
72 cm
132 cm
60 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Perimeter of rectangle = Circumference of circle = 2?r=2 x ( 22/7 ) x 42= 264 cm Now perimeter of rectangle = 2 x ( 6a + 5a )? 2 x (6a + 5a) = 264? a = 12Smaller side of rectangle = 5a = 60 cm

Area Problems
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:

2420 m2
1520 m2
2480 m2
2520 m2

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: (l - b) = 23 and 2(l + b) = 206 or (l + b) = 103. Solving the two equations, we get: l = 63 and b = 40. ∴ Area = (l x b) = (63 x 40) m2 = 2520 m2

Area Problems
If a regular hexagon is inscribed in a circle of radius, r then its perimeter?

9r
12r
3r
6r

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Length of each side of hexagoan = radius of circle ? its perimeter = 6r

Area Problems
The length of a rectangular field is increased by 60 % . By what percent would the width have to be decreased to maintain the same area?

60%
371/2%
75%
120%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let length = L and breadth = BLet , New breadth = ZThen, New length = ( 160 / 100) L.= 8L / 5? 8L / 5 x Z = LBor Z = 5B/8Decrease in breadth = (B-5B/8)= 3B/8? Decrease in percent = (3B/8 x1/B ) x 100 %= 371/2%

Area Problems
The area of a right angled triangle is 10 sq cm. If its perpendicular is equal to 20 cm, find its base.

4 cm
1 cm
3 cm
2 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given that, area = 10 sq cm, perpendicular = 20 cm and base = ? area = (base x Perpendicular) / 2 ? 10 = (base x 20) / 2 ? base = 1 cm

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