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Area Problems

Area Problems
The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height?

12 cm
16 cm
13 cm
14 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let height =x Then, base =2x 2x * x = 338 =>x=13

Area Problems
A rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered. If the area of the field is 680 sq. feet, how many feet of fencing will be required?

88
40
34
68

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We have: l = 20 ft and lb = 680 sq. ft. So, b = 34 ft. ∴ Length of fencing = (l + 2b) = (20 + 68) ft = 88 ft

Area Problems
A circular disc of area 0.49 ? square meters, rolls down a length of 1.76 km. The number of revolutions it makes is?

400
4000
300
600

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = ?r2 = 0.49? ? r = 0.7 mNumber of revolutions = total distance / circumference = (1.76 x 1000) / (2 x 22/7 x 0.7) = 400

Area Problems
The area of the largest circle that can be drawn inside a rectangle with sides 18cm by 14cm is

378
49
1078
154

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The diameter is equal to the shortest side of the rectangle. So radius= 14/2 = 7cm. Therefore, area of circle = (r)2 = (22/7) x 49 = 154 cm2

Area Problems
The length and breadth of a square are increased by 40% and 30% respectively. The area of a resulting rectangle exceeds the area of the square by?

42%
82%
None of these
62%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let the side of the square = 100 m So area of square = 100 x 100 = 10000.New length = 140 m, New breadth = 130 mIncrease in area = [(140 x 130) - (100 x 100)] m2= 8200 m2? Required increase percent = (8200/ 10000) x 100 % = 82%

Area Problems
The area of sector of a circle of radius 5 cm, formed by an arc of length 3.5 cm is?

35 sq.cms
55 sq.cms
17.5 sq.cms
8. 75 sq.cms

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of sector = ( arc length x radius ) / 2 cm2= (3.5 x 5 ) / 2= 8.75 cm2

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