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Area Problems

Area Problems
The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height?

16 cm
12 cm
13 cm
14 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let height =x Then, base =2x 2x * x = 338 =>x=13

Area Problems
In ? ABC ,sides BC = 10 cm and height AD = 4.4 cm. If AC = 11 cm. Then altitude BE equals?

5 cm
4 cm
5.6 cm
5.5 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

We know that area of triangle = ( base x height ) / 2So area of triangle = (BC x AD) / 2 = (AC x BE) / 2 ? (10 x 4.4) / 2 = (11 x h) / 2? h= (10 x 4.4)/11 = 4 cm

Area Problems
The area of the sector of a circle, whose radius is 12 meters and whose angle at the centre is 42, is?

26.4 sq. meters
52.8 sq. meters
79.2 sq. meters
39.6 sq. meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area of the sector = [(22/7) x 12 x 12] x [42°/360°] m2 = 52.8 m2

Area Problems
The Area of a square is 50 sq. units. Then the area of the circle drawn on its diagonal is?

100? sq. units
50? sq. units
None of theas
25? sq. units

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Area = (Diagonal)2 / 2 = 50? Diagonal = 10 units ? Radius of required circle = 5 unitsIts area = [? x (5)2 ] cm2= 25? units2

Area Problems
The length of a rectangular plot is 20 metres more than its breadth. If the cost of fencing the plot @ 26.50 per metre is Rs. 5300, what is the length of the plot in metres?

None of these
Data inadequate
120
40

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = x metres. Then, length = (x + 20) metres. Perimeter = ❨ 5300 ❩ m = 200 m. 26.50 ∴ 2[(x + 20) + x] = 200 ⟹ 2x + 20 = 100 ⟹ 2x = 80 ⟹ x = 40. Hence, length = x + 20 = 60 m

Area Problems
A towel, when bleached, was found to have lost 20% of its length and 10% of its breadth. The percentage of decrease in area is:

28%
10.08%
20%
10%

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let original length = x and original breadth = y. Decrease in area = xy - ❨ 80 x x 90 y ❩ 100 100 = ❨ xy - 18 xy ❩ 25 = 7 xy. 25 ∴ Decrease % = ❨ 7 xy x 1 x 100 ❩% = 28%

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