Area Problems The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height? 13 cm 12 cm 16 cm 14 cm 13 cm 12 cm 16 cm 14 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let height =x Then, base =2x 2x * x = 338 =>x=13
Area Problems The ratio of the area of the circumcircle and the incircle of a square is 1 : ?2 2 : 1 ?2 : 1 1 : 2 1 : ?2 2 : 1 ?2 : 1 1 : 2 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of the areas of the circumcircle and incircle of a square = [(Diagonal)2?] / [(Side)2?]= [(Side x ?2)2] / (Side)2 = 2/1 or 2 : 1
Area Problems The area of a trapezium is 384 sq.cm 2. If its parallel sides are in ratio 3 : 5 and the perpendicular distance between them be 12 cm, The smaller of parallel sides is? 36 cm 24 cm 30 cm 20 cm 36 cm 24 cm 30 cm 20 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the sides of trapezium be 5k and 3k, respectively According to the question, (1/2) x [(5k + 3k) x 12] = 384? 8k = (384 x 2)/12 = 64 ? k = 64/8 = 8 cmLength of smaller of the parallel sides = 8 x 3 = 24 cm
Area Problems Find the area of a rectangle having 15m length and 8m breadth. 120 sq m 111 sq m 125 sq m 115 sq m 120 sq m 111 sq m 125 sq m 115 sq m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Required area = Length x Breadth= 15 x 8 = 120 sq m
Area Problems Angles of a quadrilateral are in the ratio 3 : 4 : 5 : 8. The smallest angle is 54° 18° 40° 36° 54° 18° 40° 36° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let First angle = 3kSecond angle = 4kThird angle = 5k and Fourth angle = 8kWe know 3k + 4k + 5k + 8k = 360°? 20k = 360° ? k = 18 °Measure of smallest angle = 3k =3 x 18 ° = 54 °
Area Problems If the ratio of the area of two square is 9 : 1 the ratio of their perimeters is? 1:3 3:1 9:1 3:4 1:3 3:1 9:1 3:4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the area of square be (9x)2 m2 and (x2) m2Then, their sides are (3x) m and x metres respectively? Ratio of their perimeters = 12x / 4x=3:1
EXAMIANS