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Area Problems

Area Problems
The base of a parallelogram is twice its height. If the area of the parallelogram is 338 sq.cm. Find its height?

14 cm
13 cm
16 cm
12 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let height =x Then, base =2x 2x * x = 338 =>x=13

Area Problems
The sides of a triangle area in the ratio of 1/3 : 1/4 : 1/5 and its perimeter is 94 cm. Find the length of the smallest side of the triangle .

27 cm
22.5 cm
18 cm
24 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given ratio = 1/3 : 1/4 : 1/5 = 20 : 15 : 12Let length of the sides be 20k, 15k and 12k.Then, according to the question,20k + 15k + 12k = 94? 47k = 94? k = 94/47 = 2Smallest side = 12k = 12 x 2 = 24 cm

Area Problems
If the side of a square is increased by 25%, then how much percent does its area get increased?

125
50
156.25
56.25

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let area 100 m2Then, side = 10 m New side = 125 % of 10= (125/100) x 10= 12.5 m New area = 12.5 x 12.5 m2=(12.5)2 sq. m? Increase in area = (12.5)2 - (10)2 m2= 22.5 x 2.5 m2=56.25 m2% Increase = 56.25 %

Area Problems
A circular wire of radius 42 cm is cut and bent in the form of a rectangle whose sides are in the ratio of 6: 5 . The smaller side of the rectangle is?

132 cm
30 cm
60 cm
72 cm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Perimeter of rectangle = Circumference of circle = 2?r=2 x ( 22/7 ) x 42= 264 cm Now perimeter of rectangle = 2 x ( 6a + 5a )? 2 x (6a + 5a) = 264? a = 12Smaller side of rectangle = 5a = 60 cm

Area Problems
A rectangular plot is half as long again as it broad. The area of the lawn is 2/3 hectares. The length of the plot is?

66.66 meters
33 meters
100 meters
(100/ ? 3 ) meters

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Let breadth = b meters. then, length = 3b/2 meters ? b x 3b/2 = 2/3 X 10000? b2 = (4 x 10000)/9? b = ( 2 X 100)/3 m ? Length = (3/2) x (2/3) x 100 m= 100 m

Area Problems
The radius of a circular field is 25 m. Find the area of the field.

135 ? sq m
125 ? sq m
625 ? sq m
25 ? sq m

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Required area = ?r2 = ? x 25 x 25 = 625? sq m.

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