Area Problems The area of circle is 38.5 sq. cm. Its circumference is? 121 cm 11 cm 6.20 cm 22 cm 121 cm 11 cm 6.20 cm 22 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? ( 22 x r2) / 7 = 38.5? r2 =(38.5 x 7) /22? r = 3.5 cm? Circumference = 2 x (22/7) x 3.5 cm= 22 cm
Area Problems If the length of diagonal AC of a square ABCD is 5.2 cm then area of the square ABCD is? 10 sq.cm 13.52 sq.cm 15.12 sq.cm 12.62 sq.cm 10 sq.cm 13.52 sq.cm 15.12 sq.cm 12.62 sq.cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 x (Diagonal)2= (1/2) x 5.2 x 5.2 cm2= 13.52 cm2
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 10.5 meters 21 meters 7 meters 5.25 meters 10.5 meters 21 meters 7 meters 5.25 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
Area Problems The altitude of an equilateral triangle of side 2 ? 3 cm is? 1/2 cm ? 3/4 ? 3/2 cm 3 cm 1/2 cm ? 3/4 ? 3/2 cm 3 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 1/2 x 2 ? x h = ?3/4 x (2 ?3)2? h = 3 cm.
Area Problems The area of a circular field is 13.86 hectares . The cost of fencing it at the rate of 20 paisa per meter is? Rs. 198 Rs. 264 Rs. 324 Rs. 277.20 Rs. 198 Rs. 264 Rs. 324 Rs. 277.20 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 22/7 x r2 = 13.86 x 10000? r2 = (13.86 x 10000 x 7) / 22? r = 210 m ? Circumference = [2 x (22/7) x 210 ] m = 1320 m Cost of fencing = Rs. (1320 x 20)/100= Rs . 264
Area Problems The ratio of the area of square of side a and equilateral triangle of side a is? 2 :1 4 :3 2 : ?3 4 : ?3 2 :1 4 :3 2 : ?3 4 : ?3 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Ratio of area = a2/ ?(3/4) a2= 4/?3 = 4:?3
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