Area Problems The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field? 50 m 20 m 30 m 40 m 50 m 20 m 30 m 40 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x meters. Then, Length = 115x / 100 meters Given that, X × (115X / 100) = 460 => X = 20
Area Problems The difference between the circumference and the radius of a circle is 37 cm. The area of a circle is? 148 sq. cm 154 sq. cm 259 sq. cm 111 sq. cm 148 sq. cm 154 sq. cm 259 sq. cm 111 sq. cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP ? 2?r - r = 37? [(2 x 22/7) -1]r= 37? 37r / 7= 37? r = 7 So, area of the circle =(22/7) x 7 x 7 cm2= 154 cm2
Area Problems What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad? 844 814 820 840 844 814 820 840 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. Area of each tile = (41 x 41) cm2. ∴ Required number of tiles = ❨ 1517 x 902 ❩ = 814
Area Problems Area of a square is 1/2 hectare. The diagonal of the square is? 100 meter 50? 2 meter 250 meter 50 meter 100 meter 50? 2 meter 250 meter 50 meter ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1/2 hectare = 10000 / 2 m2= 5000 m2Again Area = 1/2 x (Diagonal)2So 1/2 x (Diagonal)2 = 5000m2? Diagonal2= 10000 ? Diagonal = 100
Area Problems A room 5.44 m x 3.75 m is to be paved with square tiles. the least number of tiles required to cover the floor is? 184 162 192 176 184 162 192 176 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of the room =(544 x 374) cm2size of largest square tile = H.C.F. of 544 & 374 = 34 cm Area of 1 tile = (34 x 34) cm2? Least number of tiles required = (544 x 374) / (34 x 34) = 176
Area Problems Find the area of the trapezium, whose parallel sides are 12 cm and 10 cm, and distance between the parallel sides is 14 cm? 154 sq.com 186 sq.com 164 sq.com 121 sq.com 154 sq.com 186 sq.com 164 sq.com 121 sq.com ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area of trapezium = 1/2 x (Sum of parallel sides) x (Distance between Parallel sides) = 1/2 x (12 + 10) x 14 = 22 x 14/2 = 22 x 7 = 154 sq. cm
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