Area Problems The area of a rectangle is 460 square metres. If the length is 15% more than the breadth, what is the breadth of the rectangular field? 50 m 30 m 20 m 40 m 50 m 30 m 20 m 40 m ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = x meters. Then, Length = 115x / 100 meters Given that, X × (115X / 100) = 460 => X = 20
Area Problems If the radius of a circle be reduced by 50%. Its area is reduced by? 39.5% 31.5% 34.5% 65.5% 39.5% 31.5% 34.5% 65.5% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Original area = ? x (r/2)2 = ?r2/4Reduction in area = ? r2 - 3? r2/4? Reduction per cent = [ 3?r2/4 x 4/(?r2) x 100 ] %= 75%
Area Problems A circular road runs rounds a circular ground. If the difference between the circumference of the outer circle and the inner circle is 66 meters, the width of the road is? 5.25 meters 10.5 meters 7 meters 21 meters 5.25 meters 10.5 meters 7 meters 21 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let outer radius be R and inner radius be r.Then from question 2?R - 2?r = 66? 2? (R-r) = 66? (2 x 22)/7 x (R - r) = 66? (R-r) = (66 x 7) / 44= 10.5 m
Area Problems The length of hall is (4/3) times its breadth. If the area of hall be 300 square meters, the difference between the length and the breadth is? 4 meters None of these 15 meters 3 meters 4 meters None of these 15 meters 3 meters ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let breadth = b meters.Then, length = 4b/3 meters.? b x 4b/3 = 300? b2 = 300 x 3/4 ? b2 = 225? b = 15Hence, required difference = [(Length) - (Breadth) ]= 4b/3 - b = b/3= 15/3 m= 5 m
Area Problems The area of a circle is increased by 22 sq cm when its radius is increased by 1 cm. Find the original radius of the circle. 3 cm 6 cm 3.5 cm 3.2 cm 3 cm 6 cm 3.5 cm 3.2 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let original radius be r.Then, according to the questions,? (r + 1)2 - ?r2 = 22? ? x [(r + 1)2 - r2] = 22? (22/7) x (r + 1 + r ) x (r + 1 - r) = 22? 2r + 1 = 7 ? 2r = 6 ? r = 6/2 = 3 cm
Area Problems If the ratio of the area of two square is 9 : 1 the ratio of their perimeters is? 3:1 9:1 1:3 3:4 3:1 9:1 1:3 3:4 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the area of square be (9x)2 m2 and (x2) m2Then, their sides are (3x) m and x metres respectively? Ratio of their perimeters = 12x / 4x=3:1
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