Waste Water Engineering The amount of oxygen consumed by the aerobic bacterias which cause the aerobic biological decomposition of sewage, is known None of these Bio-Chemical Oxygen Demand (B.O.D.) Chemical Oxygen Demand (C.O.D.) Dissolved Oxygen (D.O.) None of these Bio-Chemical Oxygen Demand (B.O.D.) Chemical Oxygen Demand (C.O.D.) Dissolved Oxygen (D.O.) ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering Drop manholes at the junctions of sewer lines, are provided if Ordinary manhole cannot be built Two sewer lines intersect Invert level of a branch sewer is more than 60 cm that of the main sewer Sewer line runs along a main road Ordinary manhole cannot be built Two sewer lines intersect Invert level of a branch sewer is more than 60 cm that of the main sewer Sewer line runs along a main road ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering For evaporation and measurement of settable solids, the apparatus used, is A jar A test tube An Imhoff cone A breaker A jar A test tube An Imhoff cone A breaker ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering The porosity of sediments in sewer pipes, is usually taken as 0.012 0.011 0.01 0.013 0.012 0.011 0.01 0.013 ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering In sewers the gas generally found, is Methane (CH4) All listed here Carbon dioxide (CO2) Hydrogen sulphide (H2S) Methane (CH4) All listed here Carbon dioxide (CO2) Hydrogen sulphide (H2S) ANSWER DOWNLOAD EXAMIANS APP
Waste Water Engineering In a sludge digestion tank if the moisture content of sludge V1 litres is reduced from p1 % to p2 % the volume V2 is [(100 – P1)/(100 – P2)] V1 [(100 + P2)/(100 – P1)] V1 [(100 – P1)/(100 + P2)] V1 [(100 + P1)/(100 – P2)] V1 [(100 – P1)/(100 – P2)] V1 [(100 + P2)/(100 – P1)] V1 [(100 – P1)/(100 + P2)] V1 [(100 + P1)/(100 – P2)] V1 ANSWER DOWNLOAD EXAMIANS APP