Area Problems Square units 13 by 9 of an office area is 107 97 127 117 107 97 127 117 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Square units 13 by 9 of an office means office of length 13 units and breadth 9 units. Now its area is 13x 9 = 117 square units or units square.
Area Problems Find the perimeter of a triangle with sides equal to 6 cm, 4 cm and 5 cm. 18 cm 14 cm 15 cm 20 cm 18 cm 14 cm 15 cm 20 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Given that, a = 6 cm, b = 4 cm and c = 5 cm Required perimeter = a + b + c= 6 + 4 + 5 cm = 15 cm
Area Problems The sides of a triangular board are 13 meters, 14 meters and 15 meters. The cost of paining it at the rate of Rs. 8.75 per m 2 is? Rs. 735 Rs. 722.50 Rs. 688.80 Rs. 730.80 Rs. 735 Rs. 722.50 Rs. 688.80 Rs. 730.80 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP s = (13 + 14 + 15 ) / 2 = 21, s-a = 8 , s-b = 7, s-c= 6? Area to be painted = ? [s(s-a) (s-b) (s-c)]=? [21 x 8 x 7 x 6] m2= 84 m2? Cost of painting = Rs. (84 x 8.75) = Rs. 735
Area Problems The perimeter of an isosceles triangle is 26 cm while equal sides together measure 20 cm. The third side and each of the equal sides are respectively. 6 cm and 10 cm 8 cm and 9 cm 14 cm and 6 cm 10 cm and 8 cm 6 cm and 10 cm 8 cm and 9 cm 14 cm and 6 cm 10 cm and 8 cm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Let the third side be x.According to the question,x + 20 = 26? x = 26 - 20 = 6 cm ? Each equal side = 20/2 = 10 cm
Area Problems The cost of cultivating a square field at the rate of Rs. 160 per hectare is Rs. 1440. the cost of putting a fence around it at 75 paisa per meter is? Rs. 810 Rs. 1800 Rs. 900 Rs. 360 Rs. 810 Rs. 1800 Rs. 900 Rs. 360 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Area = 1440 / 160 hectares = 9 hectares = 90000 m2? One side = ?90000 m = 300 mSo perimeter = 4 x 300 m = 1200 m ? Cost of fencing = Rs (1200 x 75) / 100= Rs. 900
Area Problems What is the least number of squares tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad? 840 820 814 844 840 820 814 844 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm. Area of each tile = (41 x 41) cm2. ∴ Required number of tiles = ❨ 1517 x 902 ❩ = 814