Surveying Size of a theodolite is specified by the diameter of upper plate the diameter of vertical circle the diameter of lower plate the length of telescope the diameter of upper plate the diameter of vertical circle the diameter of lower plate the length of telescope ANSWER DOWNLOAD EXAMIANS APP
Surveying The latitude of a place was obtained by subtracting the zenith distance of a star from its declination, the observed star was between Zenith and pole Horizon and equator Equator and zenith Pole and horizon Zenith and pole Horizon and equator Equator and zenith Pole and horizon ANSWER DOWNLOAD EXAMIANS APP
Surveying The graduations in prismatic compassi) are invertedii) are uprightiii) run clockwise having 0° at southiv) run clockwise having 0° at northThe correct answer is (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) (ii) and (iv) (ii) and (iii) (i) and (iii) (i) and (iv) ANSWER DOWNLOAD EXAMIANS APP
Surveying For mapping any country Geodetic triangulation of greatest possible sides and accuracy is carried out Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys Primary triangles are broken down into secondary triangles of somewhat lesser accuracy All listed here Geodetic triangulation of greatest possible sides and accuracy is carried out Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys Primary triangles are broken down into secondary triangles of somewhat lesser accuracy All listed here ANSWER DOWNLOAD EXAMIANS APP
Surveying Latitude of a place is the angular distance from Greenwich to the place None of these Equator to the nearer pole Equator to the poles Greenwich to the place None of these Equator to the nearer pole Equator to the poles ANSWER DOWNLOAD EXAMIANS APP
Surveying If α, H, A and δ be the altitude, hour angle, azimuth and declination of a circumpolar star at its elongation, in latitude λ, the following relation holds good sin α = sin λ/sin δ sin A = cos δ/cos λ All listed here cos H = tan λ/tan δ sin α = sin λ/sin δ sin A = cos δ/cos λ All listed here cos H = tan λ/tan δ ANSWER DOWNLOAD EXAMIANS APP