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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 Prevention of interference with neighboring telephone lines can be done by:

Reducing skin effect
Using bundled conductors
Reducing corona
Transposing transmission lines

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SSC JE Electrical 2019 with solution SET-1
 Two coupled coils with L1 = L2 = 0.5H have a coupling coefficient of K = 0.75. The turn ratio N1 ⁄ N2 = ?

1
0.5
2
4

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The self-inductance is given as
L = μN2A/I
L ∝ N2
where
N is the number of turns of the solenoid
A is the area of each turn of the coil
l is the length of the solenoid
and μ is the permeability constant
L1/L2 = N21/N22
0.5/0.5 = N21/N22
N1/N2 = 1
 

SSC JE Electrical 2019 with solution SET-1
 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel

1 μF
0.1 μF
100 μF
50 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

When the capacitance is connected in series the total capacitance is given by
Ceq = C1 + C2 + C3………CN
Ceq = 10n
Ceq =10 × 10 = 100 μF
 

SSC JE Electrical 2019 with solution SET-1
 The cheap and temporary system of the internal wiring is?

Conduit wiring
CTS or TRS wiring
Casing-capping
Cleat wiring

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SSC JE Electrical 2019 with solution SET-1
In the circuit shown, find the equivalent resistance between A and B.

150 ohm
50 ohm
75 ohm
100 ohm

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

The resistance R3 &  R4 are connected in series
= (30 + 70) = 100Ω
Now three resistor i.e 100Ω, 100Ω & 50Ω is connected in parallel
1/Rp = 1/100 + 1/100 + 1/50
Rp = 100/4 = 25 Ω
Resistance 50Ω and 25Ω are connected in series.
Rtotal = (50 + 25)Ω
Rtotal = 75Ω
 


SSC JE Electrical 2019 with solution SET-1
 When the only current source is active in the circuit, find the current through the 10Ω resistor

0.66 A
0 A
1.66 A
1.33 A

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