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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 Two inductors of 4H and 6H are connected in series. The equivalent inductance of this combination is

2.4 H
6 H
10 H
4 H

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Total inductance when inductor are connected in series
L = L1 + L2
L = 4 + 6 =10H
 

SSC JE Electrical 2019 with solution SET-1
 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel

50 μF
100 μF
0.1 μF
1 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

When the capacitance is connected in series the total capacitance is given by
Ceq = C1 + C2 + C3………CN
Ceq = 10n
Ceq =10 × 10 = 100 μF
 

SSC JE Electrical 2019 with solution SET-1
 A magnetic circuit is applied with a current that changes at a rate of 5 A/sec. The circuit has an inductance of 2H, then the self-induced EMF is

−10 V
0.4 V
−4 V
−2.5 V

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Given
Inductance L = 2 H
Rate of change of current di/dt = 5 A/sec
Self induced EMF = − (Rate of change of current × Inductance) = −L(di/dt)
= −(5 × 2) = −10V
 

SSC JE Electrical 2019 with solution SET-1
________ is used to manufacture stay wire, earth wire, and structural components

Cadmium copper
Hard drawn copper
Galvanized steel
Nichrome

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Galvanized steel conductors do not corrode, and possess high resistance. Hence such Wires are used in telecommunications circuits, earth wires, guard wire, stray wire, etc.
 

SSC JE Electrical 2019 with solution SET-1
______ Opposes the change in circuit voltage

Resistance
Inductance
Capacitance
Inductive reactance

ANSWER DOWNLOAD EXAMIANS APP

SSC JE Electrical 2019 with solution SET-1
 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches

Cos 30°
Cos 45°
Cos 60°
Cos 10°

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

Coil Span = 8
Pole Pitch = 9 slots/pole
Slot angle (α) = 180° / Pole Pitch = 180°/9 = 20°
Pitch Factor = cos(α/2) = cos (20/2)
Pitch Factor = cos 10°
 

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