SSC JE Electrical 2019 with solution SET-1 An electric motor in which both the rotor and stator fields rotate with the same speed is called DC motor Induction motor Universal motor Synchronous motor DC motor Induction motor Universal motor Synchronous motor ANSWER EXPLANATION DOWNLOAD EXAMIANS APP In the synchronous motor, the stator and rotor rotate at the same speed.
SSC JE Electrical 2019 with solution SET-1 What would the total loss of the 2kVA transformer corresponding to maximum efficiency be, provided the transformer has the iron of 150 W and full-load copper loss of 250W? 300 W 400 W 100 W 500 W 300 W 400 W 100 W 500 W ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When variable loss becomes equal to the constant loss, efficiency is maximum.Losses = Pi + PcSince copper loss is a variable loss thereforeLosses = Pi + Pi = 2piThus at a maximum efficiency of this transformer total loss= 150 x 2 = 300 W
SSC JE Electrical 2019 with solution SET-1 The annual load factor of a generation station is equal to (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand) (No. of units actually supplied per year) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per month) ⁄ (Max. possible demand × 8760) (No. of units actually supplied per year) ⁄ (Max. possible demand) ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 Prevention of interference with neighboring telephone lines can be done by: Using bundled conductors Reducing corona Reducing skin effect Transposing transmission lines Using bundled conductors Reducing corona Reducing skin effect Transposing transmission lines ANSWER DOWNLOAD EXAMIANS APP
SSC JE Electrical 2019 with solution SET-1 An alternator has 9 slots/pole. What is the value of the pitch factor if each coil spans 8 slot pitches Cos 30° Cos 45° Cos 10° Cos 60° Cos 30° Cos 45° Cos 10° Cos 60° ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Coil Span = 8Pole Pitch = 9 slots/poleSlot angle (α) = 180° / Pole Pitch = 180°/9 = 20°Pitch Factor = cos(α/2) = cos (20/2)Pitch Factor = cos 10°
SSC JE Electrical 2019 with solution SET-1 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel 1 μF 100 μF 50 μF 0.1 μF 1 μF 100 μF 50 μF 0.1 μF ANSWER EXPLANATION DOWNLOAD EXAMIANS APP When the capacitance is connected in series the total capacitance is given byCeq = C1 + C2 + C3………CNCeq = 10nCeq =10 × 10 = 100 μF
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