SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

dA ⁄ dΦ
dΦ − dA
dΦ ⁄ dA
Φ × A

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SSC JE Electrical 2019 with solution SET-1
 Two decimal coils A and B of 1000 turns each lies in the parallel plane such that 80% of the flux produced by one coil links with the other. If a current of 5A flowing in A produces a flux of 0.05 mWb, then the flux linking with coil B is:

0.004 mWb
0.04 mWb
0.4 mWb
4 mWb

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

12A
4A
2A
120A

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SSC JE Electrical 2019 with solution SET-1
 _______ is the measuring unit of inductive susceptance

Weber
Mho
Henry
Tesla

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