SSC JE Electrical 2019 with solution SET-1
 If dΦ is the luminous flux incident normally on an area dA, then Illuminance is given as

dA ⁄ dΦ
dΦ ⁄ dA
Φ × A
dΦ − dA

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SSC JE Electrical 2019 with solution SET-1
 For a three-layer stranded wire, the number of strands in the first, second, and third layer respectively are:

1, 4 and 8
1, 6 and 12
1, 7 and 14
1, 5 and 10

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SSC JE Electrical 2019 with solution SET-1
 The Norton’s current in the circuit shown below is

4A
12A
120A
2A

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