Hydraulics and Fluid Mechanics in ME One poise is equal to 1 N-s/m2 100 N-s/m2 0.1 N-s/m2 10 N-s/m2 1 N-s/m2 100 N-s/m2 0.1 N-s/m2 10 N-s/m2 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The overall efficiency for a Pelton wheel lies between 0.85 to 0.90 0.75 to 0.85 0.50 to 0.65 0.65 to 0.75 0.85 to 0.90 0.75 to 0.85 0.50 to 0.65 0.65 to 0.75 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth ‘d’ below the free surface at which the point velocity is equal to the average velocity of flow for a uniform laminar flow with a free surface, will be (where D is the depth of flow) 0.577 D 0.423 D 0.223 D 0.707 D 0.577 D 0.423 D 0.223 D 0.707 D ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The shear stress-strain graph for a Newtonian fluid is a Straight line Hyperbolic curve Elliptical Parabolic curve Straight line Hyperbolic curve Elliptical Parabolic curve ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which of the following is an incorrect statement ? Flow nozzle is cheaper than venturimeter but has higher energy loss Coefficient of contraction of a venturimeter is unity None of these Discharge is independent of orientation of venturimeter whether it is horizontal, vertical or inclined Flow nozzle is cheaper than venturimeter but has higher energy loss Coefficient of contraction of a venturimeter is unity None of these Discharge is independent of orientation of venturimeter whether it is horizontal, vertical or inclined ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) ANSWER DOWNLOAD EXAMIANS APP
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