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Power Systems

Power Systems
Most commonly used material for insulator is

 mica
 porcelain
 glass
All of these

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Power Systems
Which power plant cannot have single unit of 100 MW capacity

  Diesel engine plant.
 Nuclear power plant.
 Hydro electric power plant.
 Steam power plant.

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Power Systems
The sequence components of the fault current are as follows: IR1 = j1.5 pu, IR2 = -j0.5 pu, IR0 = -j1. The type of fault is

 LLL
 LG
 LLG
 LL

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Power Systems
When series reactor is used in generating stations, the fault current magnitude is

 reduced
 any of the above
 remains unaffected
 increased

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Power Systems
The per unit impedance Z(pu) is given by

 ZΩ* (MVA)b/(KV)²b
 ZΩ* (MVA)b*100/(KV)²b
 ZΩ* (MVA)b/((KV)²b *100)
 ZΩ* (kVA)b/(KV)²b

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Power Systems
If the conductor diameter decreases, inductance of the line,

 increases
 decreases
None of these
 remains unaffected

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