Hydraulics and Fluid Mechanics in ME Mechanical efficiency of a centrifugal pump is the ratio of Manometric head to the energy supplied by the impeller per kN of water Energy available at the impeller to the energy supplied to the pump by the prime mover Energy supplied to the pump to the energy available at the impeller Actual work-done by the pump to the energy supplied to the pump by the prime mover Manometric head to the energy supplied by the impeller per kN of water Energy available at the impeller to the energy supplied to the pump by the prime mover Energy supplied to the pump to the energy available at the impeller Actual work-done by the pump to the energy supplied to the pump by the prime mover ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The total energy line lies over the centre line of the pipe by an amount equal to Pressure head + velocity head Pressure head - velocity head Velocity head Pressure head Pressure head + velocity head Pressure head - velocity head Velocity head Pressure head ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The relation between hydraulic efficiency (ηh), mechanical efficiency (ηm) and overall efficiency (ηo) is ηh = ηo × ηm ηm = ηm × ηh None of these ηo = ηh × ηm ηh = ηo × ηm ηm = ηm × ηh None of these ηo = ηh × ηm ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The efficiency of a hydraulic press is given by (where W = Weight lifted by ram, P = Force applied on plunger, A = Area of ram, and a = Area of plunger) (W/p) × (a/A) (W/p) × (A/a) (p/W) × (A/a) (p/W) × (a/A) (W/p) × (a/A) (W/p) × (A/a) (p/W) × (A/a) (p/W) × (a/A) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth ‘d’ below the free surface at which the point velocity is equal to the average velocity of flow for a uniform laminar flow with a free surface, will be (where D is the depth of flow) 0.423 D 0.223 D 0.707 D 0.577 D 0.423 D 0.223 D 0.707 D 0.577 D ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME When the coefficient of discharge (Cd) is 0.623, then the general equation for discharge over a rectangular weir is 1.84(L - nH)H2 1.84(L - nH)H3 1.84(L - 0.1nH)H3/2 1.84(L - 0.1nH)H5/2 1.84(L - nH)H2 1.84(L - nH)H3 1.84(L - 0.1nH)H3/2 1.84(L - 0.1nH)H5/2 ANSWER DOWNLOAD EXAMIANS APP
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