MGVCL Exam Paper (30-07-2021 Shift 1) Match the following A = (ii), B = (i), C = (iii) A = (iii), B = (ii), C = (i) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) A = (ii), B = (i), C = (iii) A = (iii), B = (ii), C = (i) A = (ii), B = (iii), C = (i) A = (iii), B = (i), C = (ii) ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Bus Type - Known Parameter - Unknown ParameterLoad Bus -P, Q - V, phase angleGenerator Bus - P, V (magnitude) - Q, Voltage phase angleSlack Bus Voltage - magnitude and phase angle - P, Q
MGVCL Exam Paper (30-07-2021 Shift 1) A given solar cell has the following specifications:Open-circuit voltage, Voc: 0.7 VShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AShort-circuit current, Isc: 3.5 AIf the solar cell operates at maximum power point, calculate the efficiency. 15.70% 12.70% 14.70% 13.70% 15.70% 12.70% 14.70% 13.70% ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation is given by:Efficiency = (F.F*Voc*Isc)/Pin= (0.6*3.5*0.7)/10= 0.14702% efficiency = 14.7 %
MGVCL Exam Paper (30-07-2021 Shift 1) Find the word which is correctly spelt from the given options. Wrinkel Various Absurrd Abolishid Wrinkel Various Absurrd Abolishid ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The frequency of the emf in the stator of a 4-pole induction motor is 50 Hz, and that in the rotor is 2 Hz. What is the slip and at what speed is the motor running? 3%, 1440 rpm 3%, 1455 rpm 4%, 1455 rpm 4%, 1440 rpm 3%, 1440 rpm 3%, 1455 rpm 4%, 1455 rpm 4%, 1440 rpm ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Rotor frequency, f_r = s*f_ss = 2/50s = 0.04Ns = 120f/PNs = 1500 rpms = (Ns - Nr)/NsNr = Ns(1 - s)Nr = 1500*(1 - 0.04)Nr = 1440 rpm
MGVCL Exam Paper (30-07-2021 Shift 1) In computer networks, the nodes are the computer that routes data the computer that originates data all the mentioned above the computer that terminates data the computer that routes data the computer that originates data all the mentioned above the computer that terminates data ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) The operating time of an inverse definite minimum time (IDMT) overcurrent relay corresponding to plug-setting multiplier (PSM) = 1 and time-multiplier setting (TMS) = 1 will be zero 1 sec 3 sec infinite zero 1 sec 3 sec infinite ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Equation of operating time for IDMT relay (t) = 0.14*TMS/[(PSM^0.02) - 1]Here,PSM = TMS = 1So,t = 0.14*1/(1 - 1)t = infinite
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