Theory of Structures Inertia of a rectangular section of width and depth about an axis passing the moment of through C.G. and parallel to its width is B²D/6 BD³/12 BD²/6 BD³/6 B²D/6 BD³/12 BD²/6 BD³/6 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported beam A carries a point load at its mid span. Another identical beam B carries the same load but uniformly distributed over the entire span. The ratio of the maximum deflections of the beams A and B, will be 2/3 5/8 8/5 3/2 2/3 5/8 8/5 3/2 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A compound truss may be formed by connecting two simple rigid frames, by Three bars intersecting at a point Three bars Two bars three parallel bars Three bars intersecting at a point Three bars Two bars three parallel bars ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For determining the support reactions at A and B of a three hinged arch, points B and Care joined and produced to intersect the load line at D and a line parallel to the load line through A at D’. Distances AD, DD’ and AD’ when measured were 4 cm, 3 cm and 5 cm respectively. The angle between the reactions at A and B is 30° 60° 45° 90° 30° 60° 45° 90° ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 400 mm 200 mm 250 mm 300 mm 400 mm 200 mm 250 mm 300 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 2N (1 + 1/m) E = 3K (1 – 2/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 2N (1 + 1/m) E = 3K (1 – 2/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
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