Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Parabolic formula Straight line formula Rankine Perry Parabolic formula Straight line formula Rankine Perry ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 300 mm 400 mm 250 mm 200 mm 300 mm 400 mm 250 mm 200 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A spring of mean radius 40 mm contains 8 action coils of steel (N = 80000 N/mm²), 4 mm in diameter. The clearance between the coils being 1 mm when unloaded, the minimum compressive load to remove the clearance, is 40 N 25 N 35 N 30 N 40 N 25 N 35 N 30 N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures At any point of a beam, the section modulus may be obtained by dividing the moment of inertia of the section by Maximum tensile stress at the section Depth of the neutral axis Depth of the section Maximum compressive stress at the section Maximum tensile stress at the section Depth of the neutral axis Depth of the section Maximum compressive stress at the section ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) None of these A uniformly distributed load w/unit length An isolated load at mid span A load varying linearly from zero at one end to w at the other end None of these A uniformly distributed load w/unit length An isolated load at mid span A load varying linearly from zero at one end to w at the other end ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For the close coil helical spring of the maximum deflection is 4W²D3n/d4N 8WD3n/d4N WD3n/d4N 2WD3n/d4N 4W²D3n/d4N 8WD3n/d4N WD3n/d4N 2WD3n/d4N ANSWER DOWNLOAD EXAMIANS APP
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