Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Rankine Parabolic formula Perry Straight line formula Rankine Parabolic formula Perry Straight line formula ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The moment of inertia of a triangular section (height h, base b) about its base, is bh³/12 b²h/12 b³h/12 bh²/12 bh³/12 b²h/12 b³h/12 bh²/12 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good E = 3K (1 – 2/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 2N (1 + 1/m) E = 3K (1 – 2/m) All of these (3/2)K (1 – 2/m) = N (1 + 1/m) E = 2N (1 + 1/m) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A masonry dam (density = 20,000 N/m³) 6 m high, one metre wide at the top and 4 m wide at the base, has vertical water face. The minimum stress at the base of the dam when the reservoir is full, will be 75000 N/m² 7500 N/m² 75 N/m² 750 N/m² 75000 N/m² 7500 N/m² 75 N/m² 750 N/m² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In case of a simply supported I-section beam of span L and loaded with a central load W, the length of elasto-plastic zone of the plastic hinge, is L/5 L/3 L/2 L/4 L/5 L/3 L/2 L/4 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For the close coil helical spring of the maximum deflection is 2WD3n/d4N 4W²D3n/d4N WD3n/d4N 8WD3n/d4N 2WD3n/d4N 4W²D3n/d4N WD3n/d4N 8WD3n/d4N ANSWER DOWNLOAD EXAMIANS APP
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