Theory of Structures In plastic analysis, the shape factor for a triangular section, is 2.5 1.5 2.34 1.34 2.5 1.5 2.34 1.34 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end None of these An isolated load at mid span A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end None of these An isolated load at mid span ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A spring of mean radius 40 mm contains 8 action coils of steel (N = 80000 N/mm²), 4 mm in diameter. The clearance between the coils being 1 mm when unloaded, the minimum compressive load to remove the clearance, is 35 N 25 N 40 N 30 N 35 N 25 N 40 N 30 N ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A masonry dam (density = 20,000 N/m³) 6 m high, one metre wide at the top and 4 m wide at the base, has vertical water face. The minimum stress at the base of the dam when the reservoir is full, will be 7500 N/m² 75 N/m² 75000 N/m² 750 N/m² 7500 N/m² 75 N/m² 75000 N/m² 750 N/m² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection due to a load W at the free end of a cantilever of length L and having flexural rigidity EI, is WL²/2EI WL3/3EI WL3/2EI WL²/3EI WL²/2EI WL3/3EI WL3/2EI WL²/3EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures If E, N, K and 1/m are modulus of elasticity, modulus of rigidity. Bulk modulus and Poisson ratio of the material, the following relationship holds good (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) E = 3K (1 – 2/m) (3/2)K (1 – 2/m) = N (1 + 1/m) All of these E = 2N (1 + 1/m) E = 3K (1 – 2/m) ANSWER DOWNLOAD EXAMIANS APP
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