Theory of Structures The equivalent length of a column of length L, having both the ends hinged, is L/2 L 2L S L/2 L 2L S ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The general expression for the B.M. of a beam of length l is the beam carries M = (wl/2) x – (wx²/2) An isolated load at mid span A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end None of these An isolated load at mid span A uniformly distributed load w/unit length A load varying linearly from zero at one end to w at the other end None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A simply supported rolled steel joist 8 m long carries a uniformly distributed load over it span so that the maximum bending stress is 75 N/mm². If the slope at the ends is 0.005 radian and the value of E = 0.2 × 106 N/mm², the depth of the joist, is 300 mm 400 mm 250 mm 200 mm 300 mm 400 mm 250 mm 200 mm ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures a uniform circular bar of diameter d and length , which extends by an The deflection of amount under a tensile pull , when it carries the same load at its mid-span, is el/2d e²l²/3d² el²/3d² ee²l/3d² el/2d e²l²/3d² el²/3d² ee²l/3d² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the maximum deflections of a simply supported beam with a central load W and of a cantilever of same length and with a load W at its free end, is 1/16 1/8 1/12 1/10 1/16 1/8 1/12 1/10 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures H V are the algebraic sums of the forces resolved horizontally and vertically respectively, M is the algebraic sum of the moments of forces about any point, for the equilibrium of the body acted upon H = 0 All of these M = 0 V = 0 H = 0 All of these M = 0 V = 0 ANSWER DOWNLOAD EXAMIANS APP
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