Theory of Structures The equivalent length of a column of length L, having both the ends hinged, is L S L/2 2L L S L/2 2L ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures parabolic arch of span and rise , is given by The equation of a y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = h/l² × (1 – x ) y = 4h/l² × (1 – x) y = 3h/l² × (1 – x) y = 2h/l² × (1 – x) y = h/l² × (1 – x ) ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then I/M = R/E = F/Y M/I = E/R = Y/F M/I = R/E = F/Y M/I = E/R = F/Y I/M = R/E = F/Y M/I = E/R = Y/F M/I = R/E = F/Y M/I = E/R = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures a uniform circular bar of diameter d and length , which extends by an The deflection of amount under a tensile pull , when it carries the same load at its mid-span, is e²l²/3d² el/2d ee²l/3d² el²/3d² e²l²/3d² el/2d ee²l/3d² el²/3d² ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures A cantilever of length ‘L’ is subjected to a bending moment ‘M’ at its free end. If EI is the flexural rigidity of the section, the deflection of the free end, is ML²/2EI ML/EI ML/2EI ML²/3EI ML²/2EI ML/EI ML/2EI ML²/3EI ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of moments of inertia of a triangular section about its base and about a centroidal axis parallel to its base, is 1 2 1.5 3 1 2 1.5 3 ANSWER DOWNLOAD EXAMIANS APP
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