Theory of Structures A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be, 15 M 16 m 13 M 14 M 15 M 16 m 13 M 14 M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The strain energy stored in a spring when subjected to greatest load without being permanently distorted, is called Proof load Proof resilience Proof stress Stiffness Proof load Proof resilience Proof stress Stiffness ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The maximum deflection of a simply supported beam of span L, carrying an isolated load at the centre of the span; flexural rigidity being EI, is WL3/24EL WL3/8EL WL3/48EL WL3/3EL WL3/24EL WL3/8EL WL3/48EL WL3/3EL ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures The ratio of the maximum deflections of a simply supported beam with a central load W and of a cantilever of same length and with a load W at its free end, is 1/10 1/16 1/12 1/8 1/10 1/16 1/12 1/8 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Slenderness ratio of a long column, is Radius of gyration divided by area of cross-section Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration Radius of gyration divided by area of cross-section Area of cross-section divided by radius of gyration Area of cross-section divided by least radius of gyration Length of column divided by least radius of gyration ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Straight line formula Perry Rankine Parabolic formula Straight line formula Perry Rankine Parabolic formula ANSWER DOWNLOAD EXAMIANS APP
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