Theory of Structures A rolled steel joist is simply supported at its ends and carries a uniformly distributed load which causes a maximum deflection of 10 mm and slope at the ends of 0.002 radian. The length of the joist will be, 16 m 14 M 15 M 13 M 16 m 14 M 15 M 13 M ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures Y are the bending moment, moment of inertia, radius of curvature, modulus of If M, I, R, E, F, and elasticity stress and the depth of the neutral axis at section, then I/M = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y M/I = R/E = F/Y I/M = R/E = F/Y M/I = E/R = Y/F M/I = E/R = F/Y M/I = R/E = F/Y ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures There are two hinged semicircular arches A, B and C of radii 5 m, 7.5 m and 10 m respectively and each carries a concentrated load W at their crowns. The horizontal thrust at their supports will be in the ratio of 2 : 1½ : 1 1 : 1 : 2 1 : 1½ : 2 None of these 2 : 1½ : 1 1 : 1 : 2 1 : 1½ : 2 None of these ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures For calculating the allowable stress of long columns σ0 = σy/n [1 - a (1/r)²]is the empirical formula, known as Rankine Straight line formula Parabolic formula Perry Rankine Straight line formula Parabolic formula Perry ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures section modulus of a square section of side B and that of a circular section of the ratio of the diameter D, is 2 /15 3 /8 /16 3 /16 2 /15 3 /8 /16 3 /16 ANSWER DOWNLOAD EXAMIANS APP
Theory of Structures In plastic analysis, the shape factor for a circular section, is 1.5 1.7 1.2 1.3 1.5 1.7 1.2 1.3 ANSWER DOWNLOAD EXAMIANS APP
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