Machine Design In the case of an elastic bar fixed at upper end and loaded by a falling weight at lower end, the shock load produced can be decreased by Remain unaffected with cross-section area Would depend upon other factors Increasing the cross-section area of bar Decreasing the cross-section area of bar Remain unaffected with cross-section area Would depend upon other factors Increasing the cross-section area of bar Decreasing the cross-section area of bar ANSWER DOWNLOAD EXAMIANS APP
Machine Design The stress induced in the belt is, Compressive stress Torsional shear stress Tensile stress Direct shear stress Compressive stress Torsional shear stress Tensile stress Direct shear stress ANSWER DOWNLOAD EXAMIANS APP
Machine Design The included angle in unified of American National threads is 60° 29° 55° 47° 60° 29° 55° 47° ANSWER DOWNLOAD EXAMIANS APP
Machine Design The distribution of the forces along the length of key fitted in a shaft Varies exponentially, being less near the torque-input end Varies exponentially, being more near the torque-input end Is uniform throughout Varies linearly Varies exponentially, being less near the torque-input end Varies exponentially, being more near the torque-input end Is uniform throughout Varies linearly ANSWER DOWNLOAD EXAMIANS APP
Machine Design A fast and loose pulley drive is used when Driven shaft is to be started or stopped whenever desired without interfering with the driving shaft Shafts are arranged parallel and rotate in the same directions Shafts are arranged at right angles and rotate in one definite direction Shafts are arranged parallel and rotate in the opposite directions Driven shaft is to be started or stopped whenever desired without interfering with the driving shaft Shafts are arranged parallel and rotate in the same directions Shafts are arranged at right angles and rotate in one definite direction Shafts are arranged parallel and rotate in the opposite directions ANSWER DOWNLOAD EXAMIANS APP
Machine Design The velocity factor for ordinary cut gears operating at velocities up to 12.5 m/s is equal to 0.75/(0.75 + √v) 6/(6 + v) 4.5/(4.5 + v) 3/(3 + v) 0.75/(0.75 + √v) 6/(6 + v) 4.5/(4.5 + v) 3/(3 + v) ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS