MGVCL Exam Paper (30-07-2021 Shift 1) In Microsoft Word, which of the following menu is used to add Headings that are displayed automatically in the top margin of all pages? Tools Menu View Menu Format Menu Insert Menu Tools Menu View Menu Format Menu Insert Menu ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A transformer designed for operation at 60 Hz supply is working at 50 Hz supply system without changing its voltage and current ratings. Compared to the full load efficiency at 60 Hz, the full load transformer efficiency at 50 Hz. increases by 30% decreases marginally remains unaltered increases marginally increases by 30% decreases marginally remains unaltered increases marginally ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) 1 terabyte is equal to 1024 kilobytes None of these 1024 bytes 1024 gigabytes 1024 kilobytes None of these 1024 bytes 1024 gigabytes ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) By inserting a plate of dielectric material between the plates of a parallel plate capacitor at constant potential, the energy stored in the capacitor is increased five times. The dielectric constant of the material is 5 1/25 1/5 25 5 1/25 1/5 25 ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Energy stored by capacitor, Q = ½CV²Dielectric constant is directly proportional to C and capacitance is proportional to the dielectrical constant
MGVCL Exam Paper (30-07-2021 Shift 1) The air envelope surrounding the earth is called ___ Atmosphere Hydrosphere Asthenosphere Lithosphere Atmosphere Hydrosphere Asthenosphere Lithosphere ANSWER DOWNLOAD EXAMIANS APP
MGVCL Exam Paper (30-07-2021 Shift 1) A coil having an inductance of 100 mH is magnetically coupled to another coil having an inductance of 900 mH. The coefficient of coupling between the coils is 0.45. Calculate the equivalent inductance if the two coils are connected in series aiding. 932 mH 1270 mH 730 mH 1135 mH 932 mH 1270 mH 730 mH 1135 mH ANSWER EXPLANATION DOWNLOAD EXAMIANS APP Mutual inductance (M) = k*√(L1*L2)k = 0.45M = 0.45*√(900*100*10⁻⁶) = 135 mHLeq = L1 + L2 + 2MLeq = 900 + 100 + 270Leq = 1270 mH
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