Mass Transfer
In case of unsaturated air

None of the listed here
Both of the options given here
Wet bulb temperature < dry bulb temperature
Dew point < wet bulb temperature

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Mass Transfer
Compound A is extracted from a solution of A + B into a pure solvent S. A Co-current unit is used for the liquid-liquid extraction. The inlet rate of the solution containing A is 200 moles of B/hr.m² and the solvent flow, rate is 400 moles of S/m². hr. The equilibrium data is represented by Y = 3X² , where Y is in moles of a A/moles of B and X is in moles A/moles of S. The maximum percentage extraction achieved in the unit is

0.25
0.7
0.9
0.5

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Mass Transfer
The relation among various mass transfer co-efficients (M.T.C) for ideal gases is given by (where, Kc & Km are M.T.C. for equimolar counter diffusion with concentration & mole fraction respectively as the driving force. and, Kp = M.T.C. for diffusion of a gas through a stagnant inert gas with pressure as driving force.)

Kc = Kp/RT = Km . RT/P
Kc = Kp . RT = Km . RT/p
Kc = Kp = Km
None of these

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