Electrical Machines In case of a compensated DC series motor, the compensating winding is provided As a separate unit. In series with the armature winding. In parallel with the field winding. In parallel with the armature winding. As a separate unit. In series with the armature winding. In parallel with the field winding. In parallel with the armature winding. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The result of slip test on a 3-phase, 20 KVA, 400 V, 50 Hz connected salient pole alternator is given below- Phase value: Vmax = 100 V, Vmin = 96 V, Imax = 10 A and I min = 7 A. The direct and quadranature axis reactances are respectively 14.28 and 5.54 Ω. 14.28 and 9.60 Ω. 8.248 and 9.60 Ω. 8.248 and 5.54 Ω. 14.28 and 5.54 Ω. 14.28 and 9.60 Ω. 8.248 and 9.60 Ω. 8.248 and 5.54 Ω. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A shunt generator is running at 1000 rpm. If flux is reduced by half, then what is the new speed? 1000. 500. 2000. 0. 1000. 500. 2000. 0. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The torque developed in IM is nearly proportional to V2. 1 / V. V. 1 / V2. V2. 1 / V. V. 1 / V2. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 400 V, 50 Hz, 30 Hp, three phase IM is drawing 50 A current at 0.8 p.f lagging. The stator and rotor copper losses are 1.5 KW and 900 W respectively. The friction and windage losses are 1050 W and core losses are 1200 W. The air gap power of the motor will be 25 kW. 23.06 kW. 26.21 kW. 24.11 kW. 25 kW. 23.06 kW. 26.21 kW. 24.11 kW. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines For P pole machine relation between electrical degrees and mechanical degrees is θelec = P/2*θmech θelec = 4/P*θmech θelec = θmech θelec = 2/P*θmech θelec = P/2*θmech θelec = 4/P*θmech θelec = θmech θelec = 2/P*θmech ANSWER DOWNLOAD EXAMIANS APP
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