Hydraulics and Fluid Mechanics in ME In a depressed nappe The pressure below the nappe is negative The pressure above the nappe is atmospheric The pressure below the nappe is atmospheric The pressure above the nappe is negative The pressure below the nappe is negative The pressure above the nappe is atmospheric The pressure below the nappe is atmospheric The pressure above the nappe is negative ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a small rectangular orifice is given by (where Cd = Coefficient of discharge for the orifice, a = Cross-sectional area of the orifice, h = Height of the liquid above the centre of the orifice) Q = (2/3). Cd × a × h Q = Cd × a × 2gh Q = (3Cd × a)/√(2h) Q = (Cd × a)/√(2gh) Q = (2/3). Cd × a × h Q = Cd × a × 2gh Q = (3Cd × a)/√(2h) Q = (Cd × a)/√(2gh) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A structure, whose width is __________ the width of the channel, is called a flumed structure. Less than More than Equal None of these Less than More than Equal None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In an immersed body, centre of pressure is Could be above or below e.g. depending on density of body and liquid Below be centre of gravity At the centre of gravity Above the centre of gravity Could be above or below e.g. depending on density of body and liquid Below be centre of gravity At the centre of gravity Above the centre of gravity ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Power required (in watts) to drive a centrifugal pump is (where Hm = Manometric head in metres, w = Specific weight in N/m3, Q = Discharge of the pump in m3/s, and ηo = Overall efficiency of the pump) (w Q) / (Hm × ηo) (w Hm Q) / ηo (w Hm) / (Q × ηo) (w Q ηo) / Hm (w Q) / (Hm × ηo) (w Hm Q) / ηo (w Hm) / (Q × ηo) (w Q ηo) / Hm ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The depth of centre of pressure (h) for a vertically immersed surface from the liquid surface is given by (where IG = Moment of inertia of the immersed surface about horizontal axis through its centre of gravity, A = Area of immersed surface, and x = Depth of centre of gravity of the immersed surface from the liquid surface) (IG/Ax̅) + x̅ (IG/Ax̅) - x̅ (IG/x̅) - Ax̅ (Ax̅/IG) + x̅ (IG/Ax̅) + x̅ (IG/Ax̅) - x̅ (IG/x̅) - Ax̅ (Ax̅/IG) + x̅ ANSWER DOWNLOAD EXAMIANS APP
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