Hydraulics and Fluid Mechanics in ME Resultant pressure of the liquid in the case of an immersed body acts through Centre of buoyancy Metacentre Centre of gravity Centre of pressure Centre of buoyancy Metacentre Centre of gravity Centre of pressure ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The divergent portion of a Venturimeter is made longer than convergent portion in order to To minimize frictional losses Both (A) and (B) Avoid the tendency of breaking away the stream of liquid None of these To minimize frictional losses Both (A) and (B) Avoid the tendency of breaking away the stream of liquid None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In case of flow through parallel pipes, The total head loss is the sum of head losses in the various pipes The head loss for all the pipes is same Both (A) and (B) The total discharge is equal to the sum of discharges in the various pipes The total head loss is the sum of head losses in the various pipes The head loss for all the pipes is same Both (A) and (B) The total discharge is equal to the sum of discharges in the various pipes ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME According to Chezy's formula, the discharge through an open channel is (where A = Area of flow, C = Chezy's constant, m = Hydraulic mean depth, and i = Uniform slope in bed) C × √(m × i) A × √(m × i) AC × √(m × i) mi × √(A × C) C × √(m × i) A × √(m × i) AC × √(m × i) mi × √(A × C) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME If cohesion between molecules of a fluid is greater than adhesion between fluid and glass, then the free level of fluid in a dipped glass tube will be Higher than the surface of liquid The same as the surface of liquid Unpredictable Lower than the surface of liquid Higher than the surface of liquid The same as the surface of liquid Unpredictable Lower than the surface of liquid ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME A tank of uniform cross-sectional area (A) containing liquid upto height (H1) has an orifice of cross-sectional area (a) at its bottom. The time required to bring the liquid level from H1 to H2 will be 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) 2A × (√H3/2 - √H3/2)/Cd × a × √(2g) 2A × √H₁/Cd × a × √(2g) 2A × √H₂/Cd × a × √(2g) 2A × (√H₁ - √H₂)/Cd × a × √(2g) ANSWER DOWNLOAD EXAMIANS APP
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