Theory of Machine If the radius of gyration of a compound pendulum about an axis through e.g. is more, then its frequency of oscillation will be Data are insufficient to determine same Less More Same Data are insufficient to determine same Less More Same ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The magnitude of linear velocity of a point B on a link AB relative to point A is, (Where ω = Angular velocity of the link AB) ω × (AB)² ω × AB (ω × AB)² ω² × AB ω × (AB)² ω × AB (ω × AB)² ω² × AB ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The two links OA and OB are connected by a pin joint at O. If the link OA turns with angular velocity ω₁ rad/s in the clockwise direction and the link OB turns with angular velocity ω₂ rad/s in the clockwise direction, then the rubbing velocity at the pin joint O is (where r = Radius of the pin at O) (ω₁ + ω₂)r ω₁.ω₂.r (ω₁ - ω₂)2r (ω₁ - ω₂)r (ω₁ + ω₂)r ω₁.ω₂.r (ω₁ - ω₂)2r (ω₁ - ω₂)r ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine Two pulleys of radii r₁ and r₂ and at distance x apart are connected by means of an open belt drive. The length of the belt is π (r₁ + r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ - r₂)²/x + 2x π (r₁ + r₂) + (r₁ - r₂)²/x + 2x π (r₁ - r₂) + (r₁ + r₂)²/x + 2x π (r₁ + r₂) + (r₁ + r₂)²/x + 2x π (r₁ - r₂) + (r₁ - r₂)²/x + 2x π (r₁ + r₂) + (r₁ - r₂)²/x + 2x π (r₁ - r₂) + (r₁ + r₂)²/x + 2x ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The velocity of any point in mechanism relative to any other point on the mechanism on velocity polygon is represented by the line At 45° to line as per (A) Not possible to determine with these data Perpendicular to line as per (A) Joining the corresponding points At 45° to line as per (A) Not possible to determine with these data Perpendicular to line as per (A) Joining the corresponding points ANSWER DOWNLOAD EXAMIANS APP
Theory of Machine The Grubler's criterion for determining the degrees of freedom (n) of a mechanism having plane motion is (where l = Number of links, and j = Number of binary joints) n = (l -1) - j n = 4(l - 1) - 3j n = 2(l - 1) - 2j n = 3(l - 1) - 2j n = (l -1) - j n = 4(l - 1) - 3j n = 2(l - 1) - 2j n = 3(l - 1) - 2j ANSWER DOWNLOAD EXAMIANS APP
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