RCC Structures Design If the diameter of longitudinal bars of a square column is 16 mm, the diameter of lateral ties should not be less than 4 mm 6 mm 5 mm 7 mm 4 mm 6 mm 5 mm 7 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The system in which high tensile alloy steel bars (silica manganese steel) are used as pre-stressing tendons, is known as Magnel-Blaton system C.L. standard system Lee-McCall system Freyssinet system Magnel-Blaton system C.L. standard system Lee-McCall system Freyssinet system ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Pick up the incorrect statement from the following: Tensile reinforcement bars of a rectangular beam Are bent up at suitable places to serve as shear reinforcement Are bent down at suitable places to serve as shear reinforcement Are maintained at bottom to provide at least local bond stress Are curtailed if not required to resist the bending moment Are bent up at suitable places to serve as shear reinforcement Are bent down at suitable places to serve as shear reinforcement Are maintained at bottom to provide at least local bond stress Are curtailed if not required to resist the bending moment ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Though the effective depth of a T-beam is the distance between the top compression edge to the centre of the tensile reinforcement, for heavy loads, it is taken as 1/10th of the span 1/16th of the span 1/8th of the span 1/12th of the span 1/10th of the span 1/16th of the span 1/8th of the span 1/12th of the span ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column of 30 cm diameter is reinforced with 6 bars 12 mm φ placed symmetrically along the circumference. If it carries a load of 40,000 kg axially, the stress is 250 kg/cm² 100 kg/cm² 175 kg/cm² 49.9 kg/cm² 250 kg/cm² 100 kg/cm² 175 kg/cm² 49.9 kg/cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/8 M = pb (b - a)²/4 M = pb (b + a)/8 M = pb (b + a)/8 ANSWER DOWNLOAD EXAMIANS APP
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