RCC Structures Design If the diameter of longitudinal bars of a square column is 16 mm, the diameter of lateral ties should not be less than 4 mm 5 mm 7 mm 6 mm 4 mm 5 mm 7 mm 6 mm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The load stress of a section can be reduced by Decreasing the lever arm Increasing the total perimeter of bars Replacing smaller bars by greater number of greater bars Replacing larger bars by greater number of small bars Decreasing the lever arm Increasing the total perimeter of bars Replacing smaller bars by greater number of greater bars Replacing larger bars by greater number of small bars ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.5 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻⁵ 3.0 × 10⁻³ 3.5 × 10⁻⁵ 3.0 × 10⁻² 3.0 × 10⁻⁵ 3.0 × 10⁻³ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Design of R.C.C. cantilever beams, is based on the resultant force at Mid span and fixed support Mid span Fixed end Free end Mid span and fixed support Mid span Fixed end Free end ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A ribbed slab is provided for Acoustic insulation All of these Thermal insulation A plain ceiling Acoustic insulation All of these Thermal insulation A plain ceiling ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t (t + c)/n = (d + n)/n (m + c)/t = n/(d + n) mc/t = n/(d - n) mc/t = (d - n)/t ANSWER DOWNLOAD EXAMIANS APP
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