RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 a² D = 0.0775 a D = 0.775 √a D = 0.775 a D = 0.775 a² D = 0.0775 a D = 0.775 √a D = 0.775 a ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Top bars are extended to the projecting parts of the combined footing of two columns L distance apart for a distance of 0.1 L from the centre edge of column One-fourth the distance of projection 0.1 L from the outer edge of column Half the distance of projection 0.1 L from the centre edge of column One-fourth the distance of projection 0.1 L from the outer edge of column Half the distance of projection ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the shear stress in a R.C.C. beam is Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided Equal or less than 5 kg/cm², no shear reinforcement is provided All of these Greater than 20 kg/cm², the size of the section is changed Greater than 4 kg/cm², but less than 20 kg/cm², shear reinforcement is provided Equal or less than 5 kg/cm², no shear reinforcement is provided All of these ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The advantage of reinforced concrete, is due to Economy because of less maintenance cost All listed here Monolithic character Fire-resisting and durability Economy because of less maintenance cost All listed here Monolithic character Fire-resisting and durability ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The effective width of a column strip of a flat slab, is Diameter of the column One-fourth the width of the panel Half the width of the panel Radius of the column Diameter of the column One-fourth the width of the panel Half the width of the panel Radius of the column ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 10 cm 15 cm 5 cm 20 cm 10 cm 15 cm 5 cm 20 cm ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS