RCC Structures Design If the bearing capacity of soil is 10 tonnes/cm² and the projection of plain concrete footing from walls, is a cm, the depth D of footing is D = 0.775 √a D = 0.0775 a D = 0.775 a D = 0.775 a² D = 0.775 √a D = 0.0775 a D = 0.775 a D = 0.775 a² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If ‘p’ is the net upward pressure on a square footing of side ‘b’ for a square column of side ‘a’, the maximum bending moment is given by M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/4 M = pb (b - a)²/8 M = pb (b + a)/8 M = pb (b + a)/8 M = pb (c - a)/4 M = pb (b - a)²/4 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design Cantilever retaining walls can safely be used for a height not more than 4 m 5 m 3 m 6 m 4 m 5 m 3 m 6 m ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The width of the flange of a T-beam should be less than Least of the above One-third of the effective span of the T-beam Breadth of the rib plus twelve times the thickness of the slab Distance between the centers of T-beam Least of the above One-third of the effective span of the T-beam Breadth of the rib plus twelve times the thickness of the slab Distance between the centers of T-beam ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/2Sb l = dt/4Sb l = dt/Sb l = dt/3Sb l = dt/2Sb l = dt/4Sb l = dt/Sb l = dt/3Sb ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the length of a combined footing for two columns l meters apart is L and the projection on the left side of the exterior column is x, then the projection y on the right side of the exterior column, in order to have a uniformly distributed load, is (where x̅ is the distance of centre of gravity of column loads). y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) y = L/2 - (l - x̅) y = L - (l - x̅) y = L/2 - (l + x̅) y = L/2 + (l - x̅) ANSWER DOWNLOAD EXAMIANS APP
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