RCC Structures Design As per IS : 1343, total shrinkage for a pre-tensioned beam, is 3.0 × 10⁻³ 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.5 × 10⁻⁵ 3.0 × 10⁻³ 3.0 × 10⁻⁵ 3.0 × 10⁻² 3.5 × 10⁻⁵ ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The width of the flange of a T-beam, which may be considered to act effectively with the rib depends upon Overall thickness of the rib Centre to centre distance between T-beams All of the listed here Breadth of the rib Overall thickness of the rib Centre to centre distance between T-beams All of the listed here Breadth of the rib ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design The pitch of the main bars in a simply supported slab, should not exceed its effective depth by Six times Five times Three times Four times Six times Five times Three times Four times ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design As the percentage of steel increases Depth of neutral axis decreases Depth of neutral axis increases Lever arm decreases Lever arm increases Depth of neutral axis decreases Depth of neutral axis increases Lever arm decreases Lever arm increases ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Ac, Asc and A are areas of concrete, longitudinal steel and section of a R.C.C. column and m and σc are the modular ratio and maximum stress in the configuration of concrete, the strength of column is σc[A + (m - 1)Asc] σc(A - Asc) + m σcAsc All listed here σcAc + m σcAsc σc[A + (m - 1)Asc] σc(A - Asc) + m σcAsc All listed here σcAc + m σcAsc ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If Sb, is the average bond stress on a bar of diameter ‘d’ subjected to maximum stress ‘t’, the length of the embedment ‘l’ is given by l = dt/3Sb l = dt/2Sb l = dt/Sb l = dt/4Sb l = dt/3Sb l = dt/2Sb l = dt/Sb l = dt/4Sb ANSWER DOWNLOAD EXAMIANS APP
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