RCC Structures Design If a rectangular pre-stressed beam of an effective span of 5 meters and carrying a total load 3840 kg/m, is designed by the load balancing method, the central dip of the parabolic tendon should be 20 cm 15 cm 10 cm 5 cm 20 cm 15 cm 10 cm 5 cm ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If C is creep coefficient, f is original pre-stress in concrete, m is modular ratio, E is Young's modulus of steel and e is shrinkage strain, the combined effect of creep and shrinkage is: (C - 1) mf - eE (C - 1) mf + eE (1 - C) mf - eE (1 - C) mf + eE (C - 1) mf - eE (C - 1) mf + eE (1 - C) mf - eE (1 - C) mf + eE ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design A simply supported beam 6 m long and of effective depth 50 cm, carries a uniformly distributed load 2400 kg/m including its self weight. If the lever arm factor is 0.85 and permissible tensile stress of steel is 1400 kg/cm², the area of steel required, is 17 cm² 14 cm² 15 cm² 16 cm² 17 cm² 14 cm² 15 cm² 16 cm² ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design If the width of the foundation for two equal columns is restricted, the shape of the footing generally adopted, is Rectangular Trapezoidal Square Triangular Rectangular Trapezoidal Square Triangular ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design An R.C.C. column is treated as long if its slenderness ratio is greater than 50 40 35 30 50 40 35 30 ANSWER DOWNLOAD EXAMIANS APP
RCC Structures Design In a doubly-reinforced beam if ‘c’ and ‘t’ are stresses in concrete and tension reinforcement, ‘d’ is the effective depth and ‘n’ is depth of critical neutral axis, the following relationship holds good mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t mc/t = n/(d - n) (m + c)/t = n/(d + n) (t + c)/n = (d + n)/n mc/t = (d - n)/t ANSWER DOWNLOAD EXAMIANS APP
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