Surveying If ‘δ’ is the declination of the star and ‘φ’ is the latitude of the observer, then the azimuth of the star at elongation is given by sin z = sec φ . cos δ tan z = sec φ . cos δ None of these cos z = sec φ . cos δ sin z = sec φ . cos δ tan z = sec φ . cos δ None of these cos z = sec φ . cos δ ANSWER DOWNLOAD EXAMIANS APP
Surveying The most convenient co-ordinate system for specifying the relative positions of heavenly bodies on the celestial sphere, is Declination and right ascension system Declination and altitude system Declination and hour angle system Altitude and azimuth system Declination and right ascension system Declination and altitude system Declination and hour angle system Altitude and azimuth system ANSWER DOWNLOAD EXAMIANS APP
Surveying The latitude of the observer's position, is All listed here Elevation of the elevated pole Angular distance along the observer's meridian between equator and the observer Declination of the observer's zenith All listed here Elevation of the elevated pole Angular distance along the observer's meridian between equator and the observer Declination of the observer's zenith ANSWER DOWNLOAD EXAMIANS APP
Surveying If a star whose declination is 60° N culminates at zenith, its altitude at the lower culmination, is 10° 20° 40° 30° 10° 20° 40° 30° ANSWER DOWNLOAD EXAMIANS APP
Surveying The circle in which a plane tangent to the earth's surface at the point of observation, intersects the celestial sphere, is called True horizon Visible horizon Sensible horizon Celestial horizon True horizon Visible horizon Sensible horizon Celestial horizon ANSWER DOWNLOAD EXAMIANS APP
Surveying If the horizontal distance between the staff point and the point of observation is d, then the error due to curvature of earth is proportional to 1/d d 1/d2 d2 1/d d 1/d2 d2 ANSWER DOWNLOAD EXAMIANS APP
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