Refrigeration and Air Conditioning If a heat pump cycle operates between the condenser temperature of +27°C and evaporator temperature of -23°C, then the Carnot COP will be 6 1.2 5 0.2 6 1.2 5 0.2 ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The capacity of a domestic refrigerator is in the range of 1 to 3 TR 3 to 5 TR 5 to 7 TR 0.1 to 0.3 TR 1 to 3 TR 3 to 5 TR 5 to 7 TR 0.1 to 0.3 TR ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The coefficient of performance (C.O.P.) of a refrigerator working as a heat pump is given by O.P)P = ( O.P.)P = ( O.P.)R + 2 ( O.P)R O.P)R - 1 ( O.P.)P = ( ( O.P.)R + 1 ( O.P)P = ( O.P)P = ( O.P.)P = ( O.P.)R + 2 ( O.P)R O.P)R - 1 ( O.P.)P = ( ( O.P.)R + 1 ( O.P)P = ( ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The bypass factor for a cooling coil Increases with increase in velocity of air passing through it Decreases with increase in velocity of air passing through it May increase or decrease with increase in velocity of air passing through it depending upon the condition of air entering Remains unchanged with increase in velocity of air passing through it Increases with increase in velocity of air passing through it Decreases with increase in velocity of air passing through it May increase or decrease with increase in velocity of air passing through it depending upon the condition of air entering Remains unchanged with increase in velocity of air passing through it ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning On the pressure-enthalpy diagram, condensation and desuperheating is represented by a horizontal line because the process Takes place at constant entropy Takes place at constant temperature Involves no change in volume Takes place at constant pressure Takes place at constant entropy Takes place at constant temperature Involves no change in volume Takes place at constant pressure ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The sensible heat factor during cooling and dehumidification process is given by (where h₁ = Enthalpy of air entering the cooling coil, h₂ = Enthalpy of air leaving the cooling coil, and hA = Enthalpy of air at the end of dehumidification process) (hA - h2)/ (h1 - h2) (hA - h1)/ (h2 - h1) (h2 - hA)/ (h1 - h2) (h1 - h2)/ (hA - h2) (hA - h2)/ (h1 - h2) (hA - h1)/ (h2 - h1) (h2 - hA)/ (h1 - h2) (h1 - h2)/ (hA - h2) ANSWER DOWNLOAD EXAMIANS APP
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