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SSC JE Electrical 2019 with solution SET-1

SSC JE Electrical 2019 with solution SET-1
 Identify the machine shown in the circuit

DC short shunt compound generator
DC shunt motor
DC short shunt compound motor
DC long shunt compound generator

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SSC JE Electrical 2019 with solution SET-1
 Two inductors of 4H and 6H are connected in series. The equivalent inductance of this combination is

10 H
6 H
2.4 H
4 H

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Total inductance when inductor are connected in series
L = L1 + L2
L = 4 + 6 =10H
 

SSC JE Electrical 2019 with solution SET-1
 Relate ‘Reluctance with the following:

Weber/A
Weber/m
A/m
A-T/Weber

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The reluctance of any part of a magnetic circuit may be defined as the ratio of the drop in magnetomotive force to the flux produced in that part of the circuit. It is measured in ampere-turns/Weber and is denoted by S.
Reluctance = m.m.f ⁄ flux 
 

SSC JE Electrical 2019 with solution SET-1
 Find the frequency of rotor induced EMF of a 3-phase, 440V, 50 Hz induction motor has a slip of 10%

50Hz
2.5Hz
5Hz
25Hz

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Given Data
Voltage = 440 V
Frequency = 50 Hz
Slip = 10% =0.1
Now,
Rotor frequency = slip × frequency
= 0.1 × 50 = 5 Hz
 

SSC JE Electrical 2019 with solution SET-1
 Identify the important feature of a DC series motor

Zero starting torque
Low starting torque
Medium starting torque
High starting torque

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In DC series motor Torque (Ta) increase as the Square of armature current (Ia) Ta ∝ Ia2. So DC motor provides high starting torque.

SSC JE Electrical 2019 with solution SET-1
 Find the net capacitance of the combination in which ten capacitors of 10 μF are connected in parallel

1 μF
0.1 μF
50 μF
100 μF

ANSWER EXPLANATION DOWNLOAD EXAMIANS APP

When the capacitance is connected in series the total capacitance is given by
Ceq = C1 + C2 + C3………CN
Ceq = 10n
Ceq =10 × 10 = 100 μF
 

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