Hydraulics and Fluid Mechanics in ME Hydraulic accumulator is used for Supplying energy when main supply fails Generally high pressures to operate hydraulic machines Accumulating oil Supplying large quantities of oil for very short duration Supplying energy when main supply fails Generally high pressures to operate hydraulic machines Accumulating oil Supplying large quantities of oil for very short duration ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The efficiency of jet propulsion for a ship with inlet orifices at right angles to the direction of motion of ship is given by [(Vr - v) v]/ Vr [(Vr + v) v]/ Vr [2(Vr + v) v]/ Vr² [2(Vr - v) v]/ Vr² [(Vr - v) v]/ Vr [(Vr + v) v]/ Vr [2(Vr + v) v]/ Vr² [2(Vr - v) v]/ Vr² ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME In a footstep bearing, if the radius of the shaft is doubled, then the torque required to overcome the viscous resistance will be Four times Eight times Sixteen times Double Four times Eight times Sixteen times Double ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The hydraulic efficiency of a reaction turbine, is the ratio of Actual work available at the turbine to energy imparted to the wheel Work-done on the wheel to the energy (or head of water) actually supplied to the turbine Power produced by the turbine to the energy actually supplied by the turbine None of these Actual work available at the turbine to energy imparted to the wheel Work-done on the wheel to the energy (or head of water) actually supplied to the turbine Power produced by the turbine to the energy actually supplied by the turbine None of these ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a wholly drowned orifice is given by (where H1 = Height of water (on the upstream side) above the top of the orifice, H2 = Height of water (on the downstream side) above the bottom of the orifice, and H = Difference between two water levels on either side of the orifice) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH₁ × √(2gh) Q = Cd × bH × √(2gh) Q = Cd × bH2 × √(2gh) Q = Cd × b (H2 - H1) × √(2gh) Q = Cd × bH₁ × √(2gh) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a channel of trapezoidal section is maximum when The sloping side is equal to half the width at the top The sloping side is equal to the width at the bottom Depth of channel is equal to the width at the bottom Width of channel at the top is equal to twice the width at the bottom The sloping side is equal to half the width at the top The sloping side is equal to the width at the bottom Depth of channel is equal to the width at the bottom Width of channel at the top is equal to twice the width at the bottom ANSWER DOWNLOAD EXAMIANS APP
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