Surveying G.M.T. corresponding to given mean time, equals L.M.T. - East longitude in time None of these L.M.T. - West longitude in time L.M.T. + East longitude in time L.M.T. - East longitude in time None of these L.M.T. - West longitude in time L.M.T. + East longitude in time ANSWER DOWNLOAD EXAMIANS APP
Surveying A star in northern sphere is said to transit When its altitude is maximum When its azimuth is 180° When it is in south All listed here When its altitude is maximum When its azimuth is 180° When it is in south All listed here ANSWER DOWNLOAD EXAMIANS APP
Surveying In the prismatic compass the line of the sight does not move with the box the magnetic needle moves with the box the graduated circle is fixed to the box and the magnetic needle always remains in the N-S direction the magnetic needle and graduated circle do not move with the box the line of the sight does not move with the box the magnetic needle moves with the box the graduated circle is fixed to the box and the magnetic needle always remains in the N-S direction the magnetic needle and graduated circle do not move with the box ANSWER DOWNLOAD EXAMIANS APP
Surveying The scale of a vertical photograph of focal length ‘f’ taken from height of ‘H’ metres above M.S.L., at a point of reduced level ‘h’, is f/(H + h) (H - h)/f f/H f/(H - h) f/(H + h) (H - h)/f f/H f/(H - h) ANSWER DOWNLOAD EXAMIANS APP
Surveying The altitude of a heavenly body is its angular distance, measured on the vertical circle passing through the body, above Horizon Equator None of these Pole Horizon Equator None of these Pole ANSWER DOWNLOAD EXAMIANS APP
Surveying If θ and δ be the latitude of an observer and declination of a heavenly body respectively, the upper culmination of the body will be south of zenith if its zenith distance, is ½ (θ - δ) θ - δ θ + δ δ - θ ½ (θ - δ) θ - δ θ + δ δ - θ ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS