Refrigeration and Air Conditioning Formation of frost on evaporator in refrigerator Can be avoided by proper design Results in loss of heat due to poor heat transfer Increases heat transfer rate Is immaterial Can be avoided by proper design Results in loss of heat due to poor heat transfer Increases heat transfer rate Is immaterial ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The formation of frost on cooling coils in a refrigerator Reduces power consumption Increases power consumption Increases heat transfer Improves C.O.P. of the system Reduces power consumption Increases power consumption Increases heat transfer Improves C.O.P. of the system ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The evolution of heat of solution takes place in ammonia absorption plant when Lithium bromide mixes with ammonia Ammonia vapour is driven out of solution Ammonia vapour goes into solution Weak solution mixes with strong solution Lithium bromide mixes with ammonia Ammonia vapour is driven out of solution Ammonia vapour goes into solution Weak solution mixes with strong solution ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The leaks in a refrigeration system using Freon are detected by Using reagents Sulphur sticks which on detection gives white smoke Smelling Halide torch which on detection produces greenish flame lighting Using reagents Sulphur sticks which on detection gives white smoke Smelling Halide torch which on detection produces greenish flame lighting ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The C.O.P. of a refrigerator working on a reversed Carnot cycle is (where T₁ = Lowest absolute temperature, and T₂ = Highest absolute temperature) T₂/ (T₂ - T₁) T₁ / (T₂ - T₁) (T₁ - T₂)/T₁ (T₂ - T₁)/T₁ T₂/ (T₂ - T₁) T₁ / (T₂ - T₁) (T₁ - T₂)/T₁ (T₂ - T₁)/T₁ ANSWER DOWNLOAD EXAMIANS APP
Refrigeration and Air Conditioning The atmospheric air at dry bulb temperature of 15°C enters a heating coil maintained at 40°C. The air leaves the heating coil at 25°C. The bypass factor of the heating coil is 0.6 0.376 0.67 0.4 0.6 0.376 0.67 0.4 ANSWER DOWNLOAD EXAMIANS APP
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