Electrical Machines For the purpose of starting an induction motor, star/delta switch is an equivalent to auto transformer of ratio 50% 57.7% 33.3% 66.3% 50% 57.7% 33.3% 66.3% ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines The results of a slip test for determining direct axis (Xd) and quadrature axis (Xq) reactances of a star connected salient pole alternator are given below Phase values: Vmax = 108 V ; Vmin = 96 V Imax = 12 A ; Imin = 10 A Hence the two reactances will be Xd = 9Ω and Xq = 9.6Ω Xd = 10.8Ω and Xq = 8Ω Xd = 8Ω and Xq = 10.8Ω Xd = 9.6Ω and Xq = 9Ω Xd = 9Ω and Xq = 9.6Ω Xd = 10.8Ω and Xq = 8Ω Xd = 8Ω and Xq = 10.8Ω Xd = 9.6Ω and Xq = 9Ω ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In case of a compensated DC series motor, the compensating winding is provided In parallel with the armature winding. As a separate unit. In series with the armature winding. In parallel with the field winding. In parallel with the armature winding. As a separate unit. In series with the armature winding. In parallel with the field winding. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines In above question, the output power delivered by generator G1 and G2 will be 9.6 kW, 12 kW. 6.3 kW, 9.3 kW. 5.7 kW, 8.7 kW. 9.3 kW, 9.3 kW. 9.6 kW, 12 kW. 6.3 kW, 9.3 kW. 5.7 kW, 8.7 kW. 9.3 kW, 9.3 kW. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines Fifth harmonic component of the induced voltage in three phase AC generator can be eliminated by using a winding pitch of 4 / 5. 6 / 7. 2 / 3. 5 / 6. 4 / 5. 6 / 7. 2 / 3. 5 / 6. ANSWER DOWNLOAD EXAMIANS APP
Electrical Machines A 400 V, 50 Hz, 30 Hp, three phase IM is drawing 50 A current at 0.8 p.f lagging. The stator and rotor copper losses are 1.5 KW and 900 W respectively. The friction and windage losses are 1050 W and core losses are 1200 W. The air gap power of the motor will be 26.21 kW. 24.11 kW. 23.06 kW. 25 kW. 26.21 kW. 24.11 kW. 23.06 kW. 25 kW. ANSWER DOWNLOAD EXAMIANS APP
EXAMIANS