Hydraulics and Fluid Mechanics in ME For pipes, laminar flow occurs when Roynolds number is between 2000 and 4000 more than 4000 less than 4000 less than 2000 between 2000 and 4000 more than 4000 less than 4000 less than 2000 ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The Bernoulli's equation is based on the assumption that All of these There is no loss of energy of the liquid flowing No force except gravity acts on the fluid The velocity of flow is uniform across any cross-section of the pipe All of these There is no loss of energy of the liquid flowing No force except gravity acts on the fluid The velocity of flow is uniform across any cross-section of the pipe ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME Which type of the pump is different from others in the same group? Gear pump Plunger pump Cam and piston pump Screw pump Gear pump Plunger pump Cam and piston pump Screw pump ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a large rectangular orifice is given by (where H1 = Height of the liquid above the top of the orifice, H2 = Height of the liquid above the bottom of the orifice, b = Breadth of the orifice, and Cd = Coefficient of discharge) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) Q = (2/3) Cd × b × √(2g) × (H21/2 - H11/2) Q = (2/3) Cd × b × √(2g) × (H2 - H1) Q = (2/3) Cd × b × √(2g) × (H22 - H12) Q = (2/3) Cd × b × √(2g) × (H23/2 - H13/2) ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The flow of water through the hole in the bottom of a wash basin is an example of Forced vortex Free vortex Steady flow Uniform flow Forced vortex Free vortex Steady flow Uniform flow ANSWER DOWNLOAD EXAMIANS APP
Hydraulics and Fluid Mechanics in ME The discharge through a siphon spillway is Cd × a × √(2g) × H3/2 Cd × a × √(2g) × H5/2 Cd × a × √(2gH) Cd × a × √(2g) × H2 Cd × a × √(2g) × H3/2 Cd × a × √(2g) × H5/2 Cd × a × √(2gH) Cd × a × √(2g) × H2 ANSWER DOWNLOAD EXAMIANS APP
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