Surveying For mapping any country Primary triangles are broken down into secondary triangles of somewhat lesser accuracy Geodetic triangulation of greatest possible sides and accuracy is carried out All listed here Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys Primary triangles are broken down into secondary triangles of somewhat lesser accuracy Geodetic triangulation of greatest possible sides and accuracy is carried out All listed here Secondary triangles are further broken into third and fourth order triangles, the points of which are used for detail surveys ANSWER DOWNLOAD EXAMIANS APP
Surveying The suitable contour interval for a map with scale 1 : 10000 is 10 m 5 m 2 m 20 m 10 m 5 m 2 m 20 m ANSWER DOWNLOAD EXAMIANS APP
Surveying The nearest star is so far away from the earth that the directions to it from two diametrically opposite points on the earth differs less than 0.0001 second 0.01 second 0.001 second None of these 0.0001 second 0.01 second 0.001 second None of these ANSWER DOWNLOAD EXAMIANS APP
Surveying In the prismatic compass the magnetic needle and graduated circle do not move with the box the line of the sight does not move with the box the magnetic needle moves with the box the graduated circle is fixed to the box and the magnetic needle always remains in the N-S direction the magnetic needle and graduated circle do not move with the box the line of the sight does not move with the box the magnetic needle moves with the box the graduated circle is fixed to the box and the magnetic needle always remains in the N-S direction ANSWER DOWNLOAD EXAMIANS APP
Surveying Different grades are joined together by a Transition curve Compound curve Vertical curve Reverse curve Transition curve Compound curve Vertical curve Reverse curve ANSWER DOWNLOAD EXAMIANS APP
Surveying When a star is between the pole and the horizon, the relationship between latitude (λ), zenith distance (z) and declination δ, is θ = z + δ θ = (z + δ) - 180° θ = 180° - (z + δ) θ = δ - z θ = z + δ θ = (z + δ) - 180° θ = 180° - (z + δ) θ = δ - z ANSWER DOWNLOAD EXAMIANS APP
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